Difference between revisions of "Quasi-invariant measure"
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A measure on a space that is equivalent to itself under "translations" of this space. More precisely: Let $ ( X , B ) $ | A measure on a space that is equivalent to itself under "translations" of this space. More precisely: Let $ ( X , B ) $ | ||
be a [[Measurable space|measurable space]] (that is, a set $ X $ | be a [[Measurable space|measurable space]] (that is, a set $ X $ | ||
− | with a distinguished $ \sigma $- | + | with a distinguished $ \sigma $-algebra $ B $ |
− | algebra $ B $ | ||
of subsets of it) and let $ G $ | of subsets of it) and let $ G $ | ||
be a group of automorphisms of it (that is, one-to-one transformations $ g : X \rightarrow X $ | be a group of automorphisms of it (that is, one-to-one transformations $ g : X \rightarrow X $ | ||
− | that are measurable together with their inverses $ g ^ {-} | + | that are measurable together with their inverses $ g ^ {-1} $ |
− | with respect to the $ \sigma $- | + | with respect to the $ \sigma $-algebra $ B $). |
− | algebra $ B $). | ||
A measure $ \mu $ | A measure $ \mu $ | ||
on $ ( X , B ) $ | on $ ( X , B ) $ | ||
is said to be quasi-invariant (with respect to $ G $) | is said to be quasi-invariant (with respect to $ G $) | ||
if for any $ g \in G $ | if for any $ g \in G $ | ||
− | the transformed measure $ g \mu ( A) = \mu ( g ^ {-} | + | the transformed measure $ g \mu ( A) = \mu ( g ^ {-1} A ) $, |
$ A \in B $, | $ A \in B $, | ||
− | is equivalent to the measure $ \mu $( | + | is equivalent to the measure $ \mu $ |
− | that is, these measures are absolutely continuous with respect to each other, cf. [[Absolute continuity|Absolute continuity]]). If $ X $ | + | (that is, these measures are absolutely continuous with respect to each other, cf. [[Absolute continuity|Absolute continuity]]). If $ X $ |
− | is a topological [[Homogeneous space|homogeneous space]] with a continuous locally compact group of automorphisms $ G $( | + | is a topological [[Homogeneous space|homogeneous space]] with a continuous locally compact group of automorphisms $ G $ |
− | that is, $ G $ | + | (that is, $ G $ |
acts transitively on $ X $ | acts transitively on $ X $ | ||
and is endowed with a topology such that the mapping $ G \times X \rightarrow X $, | and is endowed with a topology such that the mapping $ G \times X \rightarrow X $, | ||
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is continuous with respect to the product topology on $ G \times X $) | is continuous with respect to the product topology on $ G \times X $) | ||
and $ B $ | and $ B $ | ||
− | is the Borel $ \sigma $- | + | is the Borel $ \sigma $-algebra with respect to the topology on $ X $, |
− | algebra with respect to the topology on $ X $, | + | then there exists a quasi-invariant measure that is unique up to equivalence [[#References|[1]]]. In particular, a measure on $\mathbf R ^ {n} $ |
− | then there exists a quasi-invariant measure that is unique up to equivalence [[#References|[1]]]. In particular, a measure on $ | ||
is quasi-invariant with respect to all shifts $ x \rightarrow x + a $, | is quasi-invariant with respect to all shifts $ x \rightarrow x + a $, | ||
$ x , a \in \mathbf R ^ {n} $, | $ x , a \in \mathbf R ^ {n} $, | ||
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There exists no quasi-invariant measure on an infinite-dimensional Hilbert space with respect to the group of all translations (and so, in particular, no Haar measure). Let $ \Phi \subset H \subset \Phi ^ \prime $ | There exists no quasi-invariant measure on an infinite-dimensional Hilbert space with respect to the group of all translations (and so, in particular, no Haar measure). Let $ \Phi \subset H \subset \Phi ^ \prime $ | ||
− | be a rigged Hilbert space, with $ \Phi $ | + | be a [[rigged Hilbert space]], with $ \Phi $ |
− | a nuclear space with inner product $ ( , ) $, | + | a [[nuclear space]] with inner product $ ( , ) $, |
$ H $ | $ H $ | ||
the completion of $ \Phi $, | the completion of $ \Phi $, |
Latest revision as of 17:20, 11 March 2021
A measure on a space that is equivalent to itself under "translations" of this space. More precisely: Let $ ( X , B ) $
be a measurable space (that is, a set $ X $
with a distinguished $ \sigma $-algebra $ B $
of subsets of it) and let $ G $
be a group of automorphisms of it (that is, one-to-one transformations $ g : X \rightarrow X $
that are measurable together with their inverses $ g ^ {-1} $
with respect to the $ \sigma $-algebra $ B $).
A measure $ \mu $
on $ ( X , B ) $
is said to be quasi-invariant (with respect to $ G $)
if for any $ g \in G $
the transformed measure $ g \mu ( A) = \mu ( g ^ {-1} A ) $,
$ A \in B $,
is equivalent to the measure $ \mu $
(that is, these measures are absolutely continuous with respect to each other, cf. Absolute continuity). If $ X $
is a topological homogeneous space with a continuous locally compact group of automorphisms $ G $
(that is, $ G $
acts transitively on $ X $
and is endowed with a topology such that the mapping $ G \times X \rightarrow X $,
$ ( g , x ) \rightarrow g x $,
is continuous with respect to the product topology on $ G \times X $)
and $ B $
is the Borel $ \sigma $-algebra with respect to the topology on $ X $,
then there exists a quasi-invariant measure that is unique up to equivalence [1]. In particular, a measure on $\mathbf R ^ {n} $
is quasi-invariant with respect to all shifts $ x \rightarrow x + a $,
$ x , a \in \mathbf R ^ {n} $,
if and only if it is equivalent to Lebesgue measure. If the group of transformations is not locally compact, there need not be a quasi-invariant measure; this is the case, for example, in a wide class of infinite-dimensional topological vector spaces [2].
References
[1] | N. Bourbaki, "Elements of mathematics. Integration" , Addison-Wesley (1975) pp. Chapt.6;7;8 (Translated from French) |
[2] | I.M. Gel'fand, N.Ya. Vilenkin, "Generalized functions. Applications of harmonic analysis" , 4 , Acad. Press (1964) (Translated from Russian) |
Comments
Thus, a quasi-invariant measure is a generalization of a Haar measure on a topological group. On a locally compact group with left Haar measure $ \mu $ a measure is left quasi-invariant (quasi-invariant under left translations) if and only if it is equivalent to $ \mu $.
There exists no quasi-invariant measure on an infinite-dimensional Hilbert space with respect to the group of all translations (and so, in particular, no Haar measure). Let $ \Phi \subset H \subset \Phi ^ \prime $ be a rigged Hilbert space, with $ \Phi $ a nuclear space with inner product $ ( , ) $, $ H $ the completion of $ \Phi $, and $ \Phi ^ \prime $ the dual of $ \Phi $. Each $ f \in \Phi $ defines an element $ F _ {f} $ in $ \Phi ^ \prime $, the functional $ F _ {f} ( g) = \langle f , g\rangle $. A measure $ \mu $ on $ \Phi ^ \prime $ is quasi-invariant if $ \mu ( F _ {f} + X) = 0 $ for all $ f \in \Phi $ and $ X \subset \Phi ^ \prime $ with $ \mu ( X) = 0 $, i.e. if it is quasi-invariant with respect to the group of translations $ \{ {F _ {f} } : {f \in \Phi } \} $. There exist quasi-invariant measures on such dual spaces of nuclear spaces, [2], Chapt. IV, §5.2.
Quasi-invariant measure. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Quasi-invariant_measure&oldid=51697