# Bifunctor

A mapping $ T: \mathfrak A \times \mathfrak B \rightarrow \mathfrak C $,
defined on the Cartesian product of two categories $ \mathfrak A $
and $ \mathfrak B $
with values in $ \mathfrak C $,
which assigns to each pair of objects $ A \in \mathfrak A $,
$ B \in \mathfrak B $
some object $ C \in \mathfrak C $,
and to each pair of morphisms

$$ \alpha : A \rightarrow A ^ \prime ,\ \ \beta : B \rightarrow B ^ \prime $$

the morphism

$$ \tag{1 } T( \alpha , \beta ) : \ T(A ^ \prime , B) \rightarrow \ T(A, B ^ \prime ). $$

The following conditions

$$ \tag{2 } T(1 _ {A} , 1 _ {B} ) = \ 1 _ {T (A, B) } , $$

$$ T ( \alpha ^ \prime \circ \alpha , \beta ^ \prime \circ \beta ) = T ( \alpha , \beta ^ \prime ) \circ T ( \alpha ^ \prime , \beta ), $$

must also be met. In such a case one says that the functor $ T $ is contravariant with respect to the first argument and covariant with respect to the second.

#### Comments

What is described above is a bifunctor contravariant in its first argument and covariant in its second. A bifunctor covariant in both arguments, the more fundamental notion ([a1]), has (1) and (2) replaced by

$$ \tag{1'} T ( \alpha , \beta ): \ T (A, B) \rightarrow \ T (A ^ \prime , B ^ \prime ), $$

$$ \tag{2'} T ( \alpha ^ \prime \alpha , \beta ^ \prime \beta ) = T ( \alpha ^ \prime , \beta ^ \prime ) \circ T ( \alpha , \beta ). $$

Similarly one can define bifunctors contravariant in both arguments and covariant in the first and contravariant in the second argument.

#### References

[a1] | B. Mitchell, "Theory of categories" , Acad. Press (1965) |

**How to Cite This Entry:**

Bifunctor.

*Encyclopedia of Mathematics.*URL: http://encyclopediaofmath.org/index.php?title=Bifunctor&oldid=46056