Difference between revisions of "Normal ring"
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− | Let $R$ be a commutative ring with identity and $S$ a commutative ring containing $R$, with the same identity element. An element $s \in S$ is integral over $R$ if there are $c_i \in R$ such that $s^n + c_1s^{n-1} + \cdots + c_n = 0$. The integral closure of $R$ in $S$ is the set of all $s \in S$ which are integral over $R$. It is a subring $\bar R$ of $S$ containing $R$. If $\bar R = R$, then $R$ is said to be integrally closed in $S$ (cf. also [[ | + | Let $R$ be a [[commutative ring]] [[unital ring|with identity]] and $S$ a commutative ring containing $R$, with the same identity element. An element $s \in S$ is integral over $R$ if there are $c_i \in R$ such that $s^n + c_1s^{n-1} + \cdots + c_n = 0$. The integral closure of $R$ in $S$ is the set of all $s \in S$ which are integral over $R$. It is a subring $\bar R$ of $S$ containing $R$. If $\bar R = R$, then $R$ is said to be integrally closed in $S$ (cf. also [[Integral ring]]). |
− | A commutative ring with identity $R$ is called normal if it is reduced (i.e. has no | + | A commutative ring with identity $R$ is called normal if it is reduced (i.e. has no [[nilpotent element]]s $\neq 0$) and is integrally closed in its complete ring of fractions (cf. [[Localization in a commutative algebra]]). Thus, $R$ is normal if for each prime ideal $\mathfrak{p}$ the localization $R_{\mathfrak{p}}$ is an [[integral domain]] and is closed in its field of fractions. In some of the literature a normal ring is also required to be an integral domain. |
− | A [[Noetherian ring]] $A$ is normal if and only if it satisfies the two conditions: i) for every prime ideal $\mathfrak{p}$ of height 1, $A_{\mathfrak{p}}$ is regular (and hence a discrete valuation ring); and ii) for every prime ideal $\mathfrak{p}$ of height $\ge 2$ the depth (cf. also [[ | + | A [[Noetherian ring]] $A$ is normal if and only if it satisfies the two conditions: i) for every prime ideal $\mathfrak{p}$ of height 1, $A_{\mathfrak{p}}$ is regular (and hence a discrete valuation ring); and ii) for every prime ideal $\mathfrak{p}$ of height $\ge 2$ the depth (cf. also [[Depth of a module]]) is also $\ge 2$. (Cf. [[#References|[a3]]], p. 125.) |
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+ | [[Category:Associative rings and algebras]] |
Latest revision as of 16:09, 11 September 2016
Let $R$ be a commutative ring with identity and $S$ a commutative ring containing $R$, with the same identity element. An element $s \in S$ is integral over $R$ if there are $c_i \in R$ such that $s^n + c_1s^{n-1} + \cdots + c_n = 0$. The integral closure of $R$ in $S$ is the set of all $s \in S$ which are integral over $R$. It is a subring $\bar R$ of $S$ containing $R$. If $\bar R = R$, then $R$ is said to be integrally closed in $S$ (cf. also Integral ring).
A commutative ring with identity $R$ is called normal if it is reduced (i.e. has no nilpotent elements $\neq 0$) and is integrally closed in its complete ring of fractions (cf. Localization in a commutative algebra). Thus, $R$ is normal if for each prime ideal $\mathfrak{p}$ the localization $R_{\mathfrak{p}}$ is an integral domain and is closed in its field of fractions. In some of the literature a normal ring is also required to be an integral domain.
A Noetherian ring $A$ is normal if and only if it satisfies the two conditions: i) for every prime ideal $\mathfrak{p}$ of height 1, $A_{\mathfrak{p}}$ is regular (and hence a discrete valuation ring); and ii) for every prime ideal $\mathfrak{p}$ of height $\ge 2$ the depth (cf. also Depth of a module) is also $\ge 2$. (Cf. [a3], p. 125.)
References
[a1] | N. Bourbaki, "Elements of mathematics. Commutative algebra" , Addison-Wesley (1972) (Translated from French) |
[a2] | M. Nagata, "Local rings" , Interscience (1962) pp. Chapt. III, §23 |
[a3] | H. Matsumura, "Commutative algebra" , Benjamin (1970) |
Normal ring. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Normal_ring&oldid=34377