Talk:Multiset

I guess, the carrier $C(X)$ is required to be a finite set. Really?

Also I guess that "simple set" (in this context) means "a set" (as understood in most other contexts); but is this clear enough? Boris Tsirelson (talk) 21:29, 12 January 2016 (CET)

There seems no need for the carrier to be a finite set, but the Parikh vector is normally only defined in this case. And yes, "simple set" means set here. Richard Pinch (talk) 22:30, 12 January 2016 (CET)

When the carrier is infinite, it seems natural to ask, why the multiplicity must be finite. Boris Tsirelson (talk) 11:17, 13 January 2016 (CET)

That seems to be the prevailing convention. Richard Stanley and Gian-Carlo Rota, to name but two, use this definition. Richard Pinch (talk) 18:51, 13 January 2016 (CET)