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Difference between revisions of "Kernel of a function"

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q_\sim : x \mapsto [x]_\sim \, ,
 
q_\sim : x \mapsto [x]_\sim \, ,
 
$$
 
$$
where  $[x]_\sim\,$ is the equivalence class of $c$ under $\sim\,$.  Then the  kernel of the quotient map $q_\sim\,$ is just $\sim\,$.  This may be  regarded as the set-theoretic version of the [[First Isomorphism  Theorem]].
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where  $[x]_\sim\,$ is the equivalence class of $x$ under $\sim\,$.  Then the  kernel of the quotient map $q_\sim\,$ is just $\sim\,$.  This may be  regarded as the set-theoretic version of the [[First Isomorphism  Theorem]].

Revision as of 18:42, 19 October 2014

The equivalence relation on the domain of the function expressing the property that equivalent elements have the same image under the function.

If $f : X \rightarrow Y$ then we define the relation $\stackrel{f}{\equiv}$ by $$ x_1 \stackrel{f}{\equiv} x_2 \Leftrightarrow f(x_1) = f(x_2) \ . $$ The equivalence classes of $\stackrel{f}{\equiv}$ are the fibres of f.

Every function gives rise to an equivalence relation as kernel. Conversely, every equivalence relation $\sim\,$ on a set $X$ gives rise to a function of which it is the kernel. Consider the quotient set $X/\sim\,$ of equivalence classes under $\sim\,$ and consider the quotient map $q_\sim : X \rightarrow X/\sim$ defined by $$ q_\sim : x \mapsto [x]_\sim \, , $$ where $[x]_\sim\,$ is the equivalence class of $x$ under $\sim\,$. Then the kernel of the quotient map $q_\sim\,$ is just $\sim\,$. This may be regarded as the set-theoretic version of the First Isomorphism Theorem.

How to Cite This Entry:
Kernel of a function. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Kernel_of_a_function&oldid=33959