Difference between revisions of "Cartesian factorization"
(TeX) |
m (→References: expand bibliodata) |
||
Line 13: | Line 13: | ||
====References==== | ====References==== | ||
− | <table><TR><TD valign="top">[a1]</TD> <TD valign="top"> R.H. Bing, "The cartesian product of a certain | + | <table> |
+ | <TR><TD valign="top">[a1]</TD> <TD valign="top"> R.H. Bing, "The cartesian product of a certain nonmanifold and a line is $E^4$," ''Ann. of Math.'' , '''70''' (1959) pp. 399–412. {{ZBL|0089.39501}}</TD></TR> | ||
+ | <TR><TD valign="top">[a2]</TD> <TD valign="top"> R.J. Daverman, "Decompositions of manifolds" , Acad. Press (1986). {{ZBL|0608.57002}}</TD></TR> | ||
+ | </table> |
Latest revision as of 14:08, 28 July 2021
(in topology)
A factorization of a space into a topological product. An important problem on non-trivial Cartesian factorizations concerns the cubes $I^n$ and the Euclidean spaces $\mathbf R^n$. For instance, if a space $M$ is obtained from $\mathbf R^m$, $3\leq m<n$, by identifying the points of an arc $l\subset\mathbf R^m$ for which $\pi_1(\mathbf R^m\setminus l)\neq1$ (cf. Wild imbedding), then $M\times\mathbf R=\mathbf R^{m+1}$ and $M\times M=\mathbf R^{2m}$. Any smooth compact contractible manifold $M^m$ is a factor of an $I^n$, $n>m$. Any factor of $I^n$, $n<4$, is an $I^m$, $m<n$.
References
[1] | Itogi Nauk. Algebra. Topol. Geom. 1965 (1967) pp. 227; 243 |
Comments
Another famous example is Bing's "Dog Bone" decomposition of $3$-dimensional Euclidean space, its product with a line is homeomorphic to $4$-dimensional Euclidean space.
References
[a1] | R.H. Bing, "The cartesian product of a certain nonmanifold and a line is $E^4$," Ann. of Math. , 70 (1959) pp. 399–412. Zbl 0089.39501 |
[a2] | R.J. Daverman, "Decompositions of manifolds" , Acad. Press (1986). Zbl 0608.57002 |
Cartesian factorization. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Cartesian_factorization&oldid=32893