Difference between revisions of "Holomorph of a group"
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− | + | A concept in group theory which arose in connection with the following problem. Is it possible to include any given group $ G $ | |
+ | as a normal subgroup in some other group so that all the automorphisms of $ G $ | ||
+ | are restrictions of inner automorphisms of this large group? To solve a problem of this kind, a new group $ \Gamma $ | ||
+ | is constructed using $ G $ | ||
+ | and its [[Automorphism|automorphism]] group $ \Phi ( G) $. | ||
+ | The elements of $ \Gamma $ | ||
+ | are pairs $ ( g, \phi ) $ | ||
+ | where $ g \in G $, | ||
+ | $ \phi \in \Phi ( G) $, | ||
+ | and composition of pairs is defined by the formula | ||
− | + | $$ | |
+ | ( g _ {1} , \phi _ {1} ) ( g _ {2} , \phi _ {2} ) = \ | ||
+ | ( g _ {1} g _ {2} ^ {\phi _ {1} ^ {-} 1 } ,\ | ||
+ | \phi _ {1} \phi _ {2} ), | ||
+ | $$ | ||
− | + | where $ g _ {2} ^ {\phi _ {1} ^ {-} 1 } $ | |
+ | is the image of $ g _ {2} $ | ||
+ | under $ \phi _ {1} ^ {-} 1 $. | ||
+ | The group $ \Gamma $( | ||
+ | or a group isomorphic to it) is called the holomorph of $ G $. | ||
+ | The set of pairs of the form $ ( g, \epsilon ) $, | ||
+ | where $ \epsilon $ | ||
+ | is the identity element of $ \Phi ( G) $, | ||
+ | constitutes a subgroup that is isomorphic to the original group $ G $. | ||
+ | In a similar manner, the pairs of the form $ ( e , \phi ) $, | ||
+ | where $ e $ | ||
+ | is the identity element of $ G $, | ||
+ | constitute a subgroup isomorphic to the group $ \Phi ( G) $. | ||
+ | The formula | ||
+ | $$ | ||
+ | ( e, \phi ^ {-} 1 ) ( g, \epsilon ) ( e, \phi ) = \ | ||
+ | ( g ^ \phi , \epsilon ) | ||
+ | $$ | ||
+ | shows that $ \Gamma $ | ||
+ | is in fact a solution of the problem posed above. | ||
====Comments==== | ====Comments==== | ||
− | |||
====References==== | ====References==== | ||
<table><TR><TD valign="top">[a1]</TD> <TD valign="top"> M. Hall jr., "The theory of groups" , Macmillan (1959)</TD></TR><TR><TD valign="top">[a2]</TD> <TD valign="top"> A.G. Kurosh, "Theory of groups" , '''1''' , Chelsea (1955) (Translated from Russian)</TD></TR></table> | <table><TR><TD valign="top">[a1]</TD> <TD valign="top"> M. Hall jr., "The theory of groups" , Macmillan (1959)</TD></TR><TR><TD valign="top">[a2]</TD> <TD valign="top"> A.G. Kurosh, "Theory of groups" , '''1''' , Chelsea (1955) (Translated from Russian)</TD></TR></table> |
Latest revision as of 22:10, 5 June 2020
A concept in group theory which arose in connection with the following problem. Is it possible to include any given group $ G $
as a normal subgroup in some other group so that all the automorphisms of $ G $
are restrictions of inner automorphisms of this large group? To solve a problem of this kind, a new group $ \Gamma $
is constructed using $ G $
and its automorphism group $ \Phi ( G) $.
The elements of $ \Gamma $
are pairs $ ( g, \phi ) $
where $ g \in G $,
$ \phi \in \Phi ( G) $,
and composition of pairs is defined by the formula
$$ ( g _ {1} , \phi _ {1} ) ( g _ {2} , \phi _ {2} ) = \ ( g _ {1} g _ {2} ^ {\phi _ {1} ^ {-} 1 } ,\ \phi _ {1} \phi _ {2} ), $$
where $ g _ {2} ^ {\phi _ {1} ^ {-} 1 } $ is the image of $ g _ {2} $ under $ \phi _ {1} ^ {-} 1 $. The group $ \Gamma $( or a group isomorphic to it) is called the holomorph of $ G $. The set of pairs of the form $ ( g, \epsilon ) $, where $ \epsilon $ is the identity element of $ \Phi ( G) $, constitutes a subgroup that is isomorphic to the original group $ G $. In a similar manner, the pairs of the form $ ( e , \phi ) $, where $ e $ is the identity element of $ G $, constitute a subgroup isomorphic to the group $ \Phi ( G) $. The formula
$$ ( e, \phi ^ {-} 1 ) ( g, \epsilon ) ( e, \phi ) = \ ( g ^ \phi , \epsilon ) $$
shows that $ \Gamma $ is in fact a solution of the problem posed above.
Comments
References
[a1] | M. Hall jr., "The theory of groups" , Macmillan (1959) |
[a2] | A.G. Kurosh, "Theory of groups" , 1 , Chelsea (1955) (Translated from Russian) |
Holomorph of a group. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Holomorph_of_a_group&oldid=47243