Difference between revisions of "Closed operator"
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− | An operator | + | An operator $ A : D _ {A} \rightarrow Y $ |
+ | such that if $ x _ {n} \in D _ {A} $, | ||
+ | $ x _ {n} \rightarrow x $ | ||
+ | and $ A x _ {n} \rightarrow y $, | ||
+ | then $ x \in D _ {A} $ | ||
+ | and $ A x = y $. | ||
+ | (Here $ X , Y $ | ||
+ | are Banach spaces over the same field of scalars and $ D \subset X $ | ||
+ | is the domain of definition of $ A $.) | ||
+ | The notion of a closed operator may be extended to operators defined on separable linear topological spaces, except that instead of a sequence $ \{ x _ {n} \} $ | ||
+ | one must consider arbitrary directions (nets) $ \{ x _ \xi \} $. | ||
+ | If $ \mathop{\rm Gr} A $ | ||
+ | is the graph of $ A $, | ||
+ | then $ A $ | ||
+ | is closed if and only if $ \mathop{\rm Gr} A $ | ||
+ | is a closed subset of the Cartesian product $ X \times Y $. | ||
+ | This property is often adopted as the definition of a closed operator. | ||
− | + | The notion of a closed operator is a generalization of the notion of an operator defined and continuous on a closed subset of a Banach space. An example of a closed but not continuous operator is $ A = d / dt $, | |
+ | defined on the set $ C _ {1} [ a , b ] $ | ||
+ | of continuously-differentiable functions in the space $ C [ a , b ] $. | ||
+ | Many operators of mathematical physics are closed but not continuous. | ||
− | + | An operator $ A $ | |
+ | has a closure (i.e. is closeable) if it admits a closed extension. An operator has a closure if and only if it follows from $ x _ {n} , x _ {n} ^ \prime \in D _ {A} $, | ||
− | + | $$ | |
+ | \lim\limits x _ {n} = \lim\limits x _ {n} ^ \prime ,\ \lim\limits A x _ {n} = y ,\ \lim\limits A x _ {n} ^ \prime = y ^ \prime , | ||
+ | $$ | ||
− | + | that $ y = y ^ \prime $. | |
+ | The smallest closed extension of an operator is called its closure. A symmetric operator on a Hilbert space with dense domain of definition always admits a closure. | ||
+ | |||
+ | A bounded linear operator $ A : X \rightarrow Y $ | ||
+ | is closed. Conversely, if $ A $ | ||
+ | is defined on all of $ X $ | ||
+ | and closed, then it is bounded. If $ A $ | ||
+ | is closed and $ A ^ {-} 1 $ | ||
+ | exists, then $ A ^ {-} 1 $ | ||
+ | is also closed. Since $ A : X \rightarrow X $ | ||
+ | is closed if and only if $ A - \lambda I $ | ||
+ | is closed, it follows that $ A $ | ||
+ | is closed if the resolvent $ R _ \lambda ( A ) = ( A - \lambda I ) ^ {-} 1 $ | ||
+ | exists and is bounded for at least one value of the parameter $ \lambda \in \mathbf C $. | ||
+ | |||
+ | If $ D _ {A} $ | ||
+ | is dense in $ X $ | ||
+ | and, consequently, the adjoint operator $ A ^ {*} : D _ {A ^ {*} } \rightarrow X ^ {*} $, | ||
+ | $ D _ {A ^ {*} } \subset Y ^ {*} $, | ||
+ | is uniquely defined, then $ A ^ {*} $ | ||
+ | is a closed operator. If, moreover, $ D _ {A ^ {*} } $ | ||
+ | is dense in $ Y ^ {*} $ | ||
+ | and $ X , Y $ | ||
+ | are reflexive, then $ A $ | ||
+ | is a closeable operator and its closure is $ A ^ {**} $. | ||
A closed operator can be made bounded by introducing a new norm on its domain of definition. Let | A closed operator can be made bounded by introducing a new norm on its domain of definition. Let | ||
− | + | $$ | |
+ | \| x \| _ {0} = \| x \| _ {X} + \| Ax \| _ {Y} . | ||
+ | $$ | ||
− | Then | + | Then $ D _ {A} $ |
+ | with this new norm is a Banach space and $ A $, | ||
+ | as an operator from $ ( D _ {A} , \| \cdot \| _ {0} ) $ | ||
+ | to $ Y $, | ||
+ | is bounded. | ||
====References==== | ====References==== | ||
<table><TR><TD valign="top">[1]</TD> <TD valign="top"> K. Yosida, "Functional analysis" , Springer (1980)</TD></TR><TR><TD valign="top">[2]</TD> <TD valign="top"> T. Kato, "Perturbation theory for linear operators" , Springer (1980)</TD></TR></table> | <table><TR><TD valign="top">[1]</TD> <TD valign="top"> K. Yosida, "Functional analysis" , Springer (1980)</TD></TR><TR><TD valign="top">[2]</TD> <TD valign="top"> T. Kato, "Perturbation theory for linear operators" , Springer (1980)</TD></TR></table> | ||
− | |||
− | |||
====Comments==== | ====Comments==== |
Revision as of 17:44, 4 June 2020
An operator $ A : D _ {A} \rightarrow Y $
such that if $ x _ {n} \in D _ {A} $,
$ x _ {n} \rightarrow x $
and $ A x _ {n} \rightarrow y $,
then $ x \in D _ {A} $
and $ A x = y $.
(Here $ X , Y $
are Banach spaces over the same field of scalars and $ D \subset X $
is the domain of definition of $ A $.)
The notion of a closed operator may be extended to operators defined on separable linear topological spaces, except that instead of a sequence $ \{ x _ {n} \} $
one must consider arbitrary directions (nets) $ \{ x _ \xi \} $.
If $ \mathop{\rm Gr} A $
is the graph of $ A $,
then $ A $
is closed if and only if $ \mathop{\rm Gr} A $
is a closed subset of the Cartesian product $ X \times Y $.
This property is often adopted as the definition of a closed operator.
The notion of a closed operator is a generalization of the notion of an operator defined and continuous on a closed subset of a Banach space. An example of a closed but not continuous operator is $ A = d / dt $, defined on the set $ C _ {1} [ a , b ] $ of continuously-differentiable functions in the space $ C [ a , b ] $. Many operators of mathematical physics are closed but not continuous.
An operator $ A $ has a closure (i.e. is closeable) if it admits a closed extension. An operator has a closure if and only if it follows from $ x _ {n} , x _ {n} ^ \prime \in D _ {A} $,
$$ \lim\limits x _ {n} = \lim\limits x _ {n} ^ \prime ,\ \lim\limits A x _ {n} = y ,\ \lim\limits A x _ {n} ^ \prime = y ^ \prime , $$
that $ y = y ^ \prime $. The smallest closed extension of an operator is called its closure. A symmetric operator on a Hilbert space with dense domain of definition always admits a closure.
A bounded linear operator $ A : X \rightarrow Y $ is closed. Conversely, if $ A $ is defined on all of $ X $ and closed, then it is bounded. If $ A $ is closed and $ A ^ {-} 1 $ exists, then $ A ^ {-} 1 $ is also closed. Since $ A : X \rightarrow X $ is closed if and only if $ A - \lambda I $ is closed, it follows that $ A $ is closed if the resolvent $ R _ \lambda ( A ) = ( A - \lambda I ) ^ {-} 1 $ exists and is bounded for at least one value of the parameter $ \lambda \in \mathbf C $.
If $ D _ {A} $ is dense in $ X $ and, consequently, the adjoint operator $ A ^ {*} : D _ {A ^ {*} } \rightarrow X ^ {*} $, $ D _ {A ^ {*} } \subset Y ^ {*} $, is uniquely defined, then $ A ^ {*} $ is a closed operator. If, moreover, $ D _ {A ^ {*} } $ is dense in $ Y ^ {*} $ and $ X , Y $ are reflexive, then $ A $ is a closeable operator and its closure is $ A ^ {**} $.
A closed operator can be made bounded by introducing a new norm on its domain of definition. Let
$$ \| x \| _ {0} = \| x \| _ {X} + \| Ax \| _ {Y} . $$
Then $ D _ {A} $ with this new norm is a Banach space and $ A $, as an operator from $ ( D _ {A} , \| \cdot \| _ {0} ) $ to $ Y $, is bounded.
References
[1] | K. Yosida, "Functional analysis" , Springer (1980) |
[2] | T. Kato, "Perturbation theory for linear operators" , Springer (1980) |
Comments
The result that a closed linear operator mapping (all of) a Banach space into a Banach space is continuous is known as the closed-graph theorem.
References
[a1] | S. Goldberg, "Unbounded linear operators" , McGraw-Hill (1966) |
Closed operator. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Closed_operator&oldid=46365