Difference between revisions of "Bounded operator"
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− | + | A mapping $ A $ | |
+ | of a topological vector space $ X $ | ||
+ | into a topological vector space $ Y $ | ||
+ | such that $ A (M) $ | ||
+ | is a bounded subset in $ Y $ | ||
+ | for any bounded subset $ M $ | ||
+ | of $ X $. | ||
+ | Every operator $ A : X \rightarrow Y $, | ||
+ | continuous on $ X $, | ||
+ | is a bounded operator. If $ A : X \rightarrow Y $ | ||
+ | is a linear operator, then for $ A $ | ||
+ | to be bounded it is sufficient that there exists a neighbourhood $ U \subset X $ | ||
+ | such that $ A (U) $ | ||
+ | is bounded in $ Y $. | ||
+ | Suppose that $ X $ | ||
+ | and $ Y $ | ||
+ | are normed linear spaces and that the linear operator $ A : X \rightarrow Y $ | ||
+ | is bounded. Then | ||
− | + | $$ | |
+ | \gamma = \ | ||
+ | \sup _ {\| x \| \leq 1 } \| A x \| < \infty . | ||
+ | $$ | ||
− | and | + | This number is called the norm of the operator $ A $ |
+ | and is denoted by $ \| A \| $. | ||
+ | Then | ||
− | + | $$ | |
+ | \| A x \| \leq \| A \| \cdot \| x \| , | ||
+ | $$ | ||
− | + | and $ \| A \| $ | |
+ | is the smallest constant $ C $ | ||
+ | such that | ||
− | + | $$ | |
+ | \| A x \| \leq C \| x \| | ||
+ | $$ | ||
− | are | + | for any $ x \in X $. |
+ | Conversely, if this inequality is satisfied, then $ A $ | ||
+ | is bounded. For linear operators mapping a normed space $ X $ | ||
+ | into a normed space $ Y $, | ||
+ | the concepts of boundedness and continuity are equivalent. This is not the case for arbitrary topological vector spaces $ X $ | ||
+ | and $ Y $, | ||
+ | but if $ X $ | ||
+ | is bornological and $ Y $ | ||
+ | is a locally convex space, then the boundedness of a linear operator $ A : X \rightarrow Y $ | ||
+ | implies its continuity. If $ H $ | ||
+ | is a Hilbert space and $ A : H \rightarrow H $ | ||
+ | is a bounded symmetric operator, then the quadratic form $ \langle A x , x \rangle $ | ||
+ | is bounded on the unit ball $ K _ {1} = \{ {x } : {\| x \| \leq 1 } \} $. | ||
+ | The numbers | ||
− | + | $$ | |
+ | \beta = \ | ||
+ | \sup _ {\| x \| \leq 1 } \langle A x , x \rangle \ \ | ||
+ | \textrm{ and } \ \ | ||
+ | \alpha = \inf _ {\| x \| \leq 1 } \langle A x , x \rangle | ||
+ | $$ | ||
+ | |||
+ | are called the upper and lower bounds of the operator $ A $. | ||
+ | The points $ \alpha $ | ||
+ | and $ \beta $ | ||
+ | belongs to the spectrum of $ A $, | ||
+ | and the whole spectrum lies in the interval $ [ \alpha , \beta ] $. | ||
+ | Examples of bounded operators are: the projection operator ([[Projector|projector]]) onto a complemented subspace of a Banach space, and an [[Isometric operator|isometric operator]] acting on a Hilbert space. | ||
+ | |||
+ | If the space $ X $ | ||
+ | and $ Y $ | ||
+ | have the structure of a partially ordered set, for example are vector lattices (cf. [[Vector lattice|Vector lattice]]), then a concept of order-boundedness of an operator can be introduced, besides the topological boundedness considered above. An operator $ A : X \rightarrow Y $ | ||
+ | is called order-bounded if $ A (M) $ | ||
+ | is an order-bounded set in $ Y $ | ||
+ | for any order-bounded set $ M $ | ||
+ | in $ X $. | ||
+ | Examples: an isotone operator, i.e. an operator such that $ x \leq y $ | ||
+ | implies $ A x \leq A y $. | ||
====References==== | ====References==== | ||
<table><TR><TD valign="top">[1]</TD> <TD valign="top"> L.A. Lyusternik, V.I. Sobolev, "Elemente der Funktionalanalysis" , Akademie Verlag (1955) (Translated from Russian)</TD></TR><TR><TD valign="top">[2]</TD> <TD valign="top"> W. Rudin, "Functional analysis" , McGraw-Hill (1973)</TD></TR><TR><TD valign="top">[3]</TD> <TD valign="top"> G. Birkhoff, "Lattice theory" , ''Colloq. Publ.'' , '''25''' , Amer. Math. Soc. (1967)</TD></TR></table> | <table><TR><TD valign="top">[1]</TD> <TD valign="top"> L.A. Lyusternik, V.I. Sobolev, "Elemente der Funktionalanalysis" , Akademie Verlag (1955) (Translated from Russian)</TD></TR><TR><TD valign="top">[2]</TD> <TD valign="top"> W. Rudin, "Functional analysis" , McGraw-Hill (1973)</TD></TR><TR><TD valign="top">[3]</TD> <TD valign="top"> G. Birkhoff, "Lattice theory" , ''Colloq. Publ.'' , '''25''' , Amer. Math. Soc. (1967)</TD></TR></table> | ||
− | |||
− | |||
====Comments==== | ====Comments==== | ||
− | |||
====References==== | ====References==== | ||
<table><TR><TD valign="top">[a1]</TD> <TD valign="top"> A.E. Taylor, D.C. Lay, "Introduction to functional analysis" , Wiley (1980)</TD></TR><TR><TD valign="top">[a2]</TD> <TD valign="top"> A.C. Zaanen, "Riesz spaces" , '''II''' , North-Holland (1983)</TD></TR></table> | <table><TR><TD valign="top">[a1]</TD> <TD valign="top"> A.E. Taylor, D.C. Lay, "Introduction to functional analysis" , Wiley (1980)</TD></TR><TR><TD valign="top">[a2]</TD> <TD valign="top"> A.C. Zaanen, "Riesz spaces" , '''II''' , North-Holland (1983)</TD></TR></table> |
Latest revision as of 06:29, 30 May 2020
A mapping $ A $
of a topological vector space $ X $
into a topological vector space $ Y $
such that $ A (M) $
is a bounded subset in $ Y $
for any bounded subset $ M $
of $ X $.
Every operator $ A : X \rightarrow Y $,
continuous on $ X $,
is a bounded operator. If $ A : X \rightarrow Y $
is a linear operator, then for $ A $
to be bounded it is sufficient that there exists a neighbourhood $ U \subset X $
such that $ A (U) $
is bounded in $ Y $.
Suppose that $ X $
and $ Y $
are normed linear spaces and that the linear operator $ A : X \rightarrow Y $
is bounded. Then
$$ \gamma = \ \sup _ {\| x \| \leq 1 } \| A x \| < \infty . $$
This number is called the norm of the operator $ A $ and is denoted by $ \| A \| $. Then
$$ \| A x \| \leq \| A \| \cdot \| x \| , $$
and $ \| A \| $ is the smallest constant $ C $ such that
$$ \| A x \| \leq C \| x \| $$
for any $ x \in X $. Conversely, if this inequality is satisfied, then $ A $ is bounded. For linear operators mapping a normed space $ X $ into a normed space $ Y $, the concepts of boundedness and continuity are equivalent. This is not the case for arbitrary topological vector spaces $ X $ and $ Y $, but if $ X $ is bornological and $ Y $ is a locally convex space, then the boundedness of a linear operator $ A : X \rightarrow Y $ implies its continuity. If $ H $ is a Hilbert space and $ A : H \rightarrow H $ is a bounded symmetric operator, then the quadratic form $ \langle A x , x \rangle $ is bounded on the unit ball $ K _ {1} = \{ {x } : {\| x \| \leq 1 } \} $. The numbers
$$ \beta = \ \sup _ {\| x \| \leq 1 } \langle A x , x \rangle \ \ \textrm{ and } \ \ \alpha = \inf _ {\| x \| \leq 1 } \langle A x , x \rangle $$
are called the upper and lower bounds of the operator $ A $. The points $ \alpha $ and $ \beta $ belongs to the spectrum of $ A $, and the whole spectrum lies in the interval $ [ \alpha , \beta ] $. Examples of bounded operators are: the projection operator (projector) onto a complemented subspace of a Banach space, and an isometric operator acting on a Hilbert space.
If the space $ X $ and $ Y $ have the structure of a partially ordered set, for example are vector lattices (cf. Vector lattice), then a concept of order-boundedness of an operator can be introduced, besides the topological boundedness considered above. An operator $ A : X \rightarrow Y $ is called order-bounded if $ A (M) $ is an order-bounded set in $ Y $ for any order-bounded set $ M $ in $ X $. Examples: an isotone operator, i.e. an operator such that $ x \leq y $ implies $ A x \leq A y $.
References
[1] | L.A. Lyusternik, V.I. Sobolev, "Elemente der Funktionalanalysis" , Akademie Verlag (1955) (Translated from Russian) |
[2] | W. Rudin, "Functional analysis" , McGraw-Hill (1973) |
[3] | G. Birkhoff, "Lattice theory" , Colloq. Publ. , 25 , Amer. Math. Soc. (1967) |
Comments
References
[a1] | A.E. Taylor, D.C. Lay, "Introduction to functional analysis" , Wiley (1980) |
[a2] | A.C. Zaanen, "Riesz spaces" , II , North-Holland (1983) |
Bounded operator. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Bounded_operator&oldid=46139