Difference between revisions of "Urysohn-Brouwer lemma"
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''Urysohn–Brouwer–Tietze lemma'' | ''Urysohn–Brouwer–Tietze lemma'' | ||
− | An assertion on the possibility of extending a continuous function from a subspace of a topological space to the whole space. Let | + | An assertion on the possibility of extending a continuous function from a subspace of a topological space to the whole space. Let $ X $ |
+ | be a [[Normal space|normal space]] and $ F $ | ||
+ | a closed subset of it. Then any continuous function $ f : F \rightarrow \mathbf R $ | ||
+ | can be extended to a continuous function $ g : X \rightarrow \mathbf R $, | ||
+ | i.e. one can find a continuous function $ g $ | ||
+ | such that $ g ( x) = f ( x) $ | ||
+ | for all $ x \in F $. | ||
+ | Moreover, if $ f $ | ||
+ | is bounded, then there exists an extension $ g $ | ||
+ | such that | ||
− | + | $$ | |
+ | \sup _ {x \in F } \ | ||
+ | | f ( x) | = \sup _ {x \in X } | g ( x) | . | ||
+ | $$ | ||
− | The Urysohn–Brouwer lemma was proved by L.E.J. Brouwer and H. Lebesgue for | + | The Urysohn–Brouwer lemma was proved by L.E.J. Brouwer and H. Lebesgue for $ X = \mathbf R ^ {n} $, |
+ | by H. Tietze for an arbitrary metric space $ X $, | ||
+ | and by P.S. Urysohn in the above formulation (which may be used as a characterization of normal spaces and is thus best possible). | ||
====References==== | ====References==== | ||
<table><TR><TD valign="top">[1]</TD> <TD valign="top"> P.S. Urysohn, "Ueber die Mächtigkeit der zusammenhängenden Mengen" ''Math. Ann.'' , '''94''' (1925) pp. 262–295</TD></TR></table> | <table><TR><TD valign="top">[1]</TD> <TD valign="top"> P.S. Urysohn, "Ueber die Mächtigkeit der zusammenhängenden Mengen" ''Math. Ann.'' , '''94''' (1925) pp. 262–295</TD></TR></table> | ||
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====Comments==== | ====Comments==== |
Latest revision as of 08:27, 6 June 2020
Urysohn–Brouwer–Tietze lemma
An assertion on the possibility of extending a continuous function from a subspace of a topological space to the whole space. Let $ X $ be a normal space and $ F $ a closed subset of it. Then any continuous function $ f : F \rightarrow \mathbf R $ can be extended to a continuous function $ g : X \rightarrow \mathbf R $, i.e. one can find a continuous function $ g $ such that $ g ( x) = f ( x) $ for all $ x \in F $. Moreover, if $ f $ is bounded, then there exists an extension $ g $ such that
$$ \sup _ {x \in F } \ | f ( x) | = \sup _ {x \in X } | g ( x) | . $$
The Urysohn–Brouwer lemma was proved by L.E.J. Brouwer and H. Lebesgue for $ X = \mathbf R ^ {n} $, by H. Tietze for an arbitrary metric space $ X $, and by P.S. Urysohn in the above formulation (which may be used as a characterization of normal spaces and is thus best possible).
References
[1] | P.S. Urysohn, "Ueber die Mächtigkeit der zusammenhängenden Mengen" Math. Ann. , 94 (1925) pp. 262–295 |
Comments
This assertion is also known as the Tietze–Urysohn extension theorem, or even as the Tietze extension theorem.
References
[a1] | R. Engelking, "General topology" , Heldermann (1989) |
Urysohn-Brouwer lemma. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Urysohn-Brouwer_lemma&oldid=23095