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Difference between revisions of "Weighted average"

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$#C+1 = 4 : ~/encyclopedia/old_files/data/W097/W.0907570 Weighted average
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The quantity
 
The quantity
  
<table class="eq" style="width:100%;"> <tr><td valign="top" style="width:94%;text-align:center;"><img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/w/w097/w097570/w0975701.png" /></td> </tr></table>
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$$
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\overline{x}\; = \
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\frac{\sum _ {i = 1 }  ^ {n} p _ {i} x _ {i} }{\sum _ {i = 1 }  ^ {n} p _ {i} }
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,
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$$
  
where <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/w/w097/w097570/w0975702.png" /> are <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/w/w097/w097570/w0975703.png" /> quantities taken with respective weights <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/w/w097/w097570/w0975704.png" />.
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where $  x _ {1} \dots x _ {n} $
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are $  n $
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quantities taken with respective weights $  p _ {1} \dots p _ {n} $.

Latest revision as of 08:29, 6 June 2020


The quantity

$$ \overline{x}\; = \ \frac{\sum _ {i = 1 } ^ {n} p _ {i} x _ {i} }{\sum _ {i = 1 } ^ {n} p _ {i} } , $$

where $ x _ {1} \dots x _ {n} $ are $ n $ quantities taken with respective weights $ p _ {1} \dots p _ {n} $.

How to Cite This Entry:
Weighted average. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Weighted_average&oldid=12350