Difference between revisions of "Continuum, cardinality of the"
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− | $$\alpha^{\aleph_0}=\mathfrak c.$$ | + | The [[cardinal number]] $\mathfrak c=2^{\aleph_0}$, i.e. the cardinality of the set of all subsets of the natural numbers. The following sets have the cardinality of the continuum: 1) the set $\mathbf R$ of all real numbers; 2) the set of all points in the interval $(0,1)$; 3) the set of all irrational numbers in this interval; 4) the set of all points of the space $\mathbf R^n$, where $n$ is a positive integer; 5) the set of all transcendental numbers; and 6) the set of all continuous functions of a real variable. The cardinality of the continuum cannot be represented as a countable sum of smaller cardinal numbers. For any cardinal number $\alpha$ such that $2\leq\alpha\leq\mathfrak c$, |
+ | |||
+ | $$\alpha^{\aleph_0}=\mathfrak c \ .$$ | ||
In particular, | In particular, | ||
− | $$2^{\aleph_0}=3^{\aleph_0}=\dots=\aleph_0^{\aleph_0}=\aleph_1^{\aleph_0}=\mathfrak c^{\aleph_0}=\mathfrak c.$$ | + | $$2^{\aleph_0}=3^{\aleph_0}=\dots=\aleph_0^{\aleph_0}=\aleph_1^{\aleph_0}=\mathfrak c^{\aleph_0}=\mathfrak c \ .$$ |
− | The [[Continuum | + | By [[Cantor theorem|Cantor's theorem]] the cardinal $2^{\aleph_0}$ is strictly greater than $\aleph_0$: that is, $\mathfrak c$ is uncountable. The [[Continuum hypothesis]] states that the cardinality of the continuum is the first uncountable cardinal number, that is, |
− | $$\mathfrak c=\aleph_1.$$ | + | $$\mathfrak c=\aleph_1 \ .$$ |
====References==== | ====References==== | ||
− | <table><TR><TD valign="top">[1]</TD> <TD valign="top"> K. Kuratowski, A. Mostowski, "Set theory" , North-Holland (1968)</TD></TR></table> | + | <table> |
+ | <TR><TD valign="top">[1]</TD> <TD valign="top"> K. Kuratowski, A. Mostowski, "Set theory" , North-Holland (1968)</TD></TR> | ||
+ | </table> |
Latest revision as of 20:11, 10 January 2015
2020 Mathematics Subject Classification: Primary: 03E10 Secondary: 03E50 [MSN][ZBL]
The cardinal number $\mathfrak c=2^{\aleph_0}$, i.e. the cardinality of the set of all subsets of the natural numbers. The following sets have the cardinality of the continuum: 1) the set $\mathbf R$ of all real numbers; 2) the set of all points in the interval $(0,1)$; 3) the set of all irrational numbers in this interval; 4) the set of all points of the space $\mathbf R^n$, where $n$ is a positive integer; 5) the set of all transcendental numbers; and 6) the set of all continuous functions of a real variable. The cardinality of the continuum cannot be represented as a countable sum of smaller cardinal numbers. For any cardinal number $\alpha$ such that $2\leq\alpha\leq\mathfrak c$,
$$\alpha^{\aleph_0}=\mathfrak c \ .$$
In particular,
$$2^{\aleph_0}=3^{\aleph_0}=\dots=\aleph_0^{\aleph_0}=\aleph_1^{\aleph_0}=\mathfrak c^{\aleph_0}=\mathfrak c \ .$$
By Cantor's theorem the cardinal $2^{\aleph_0}$ is strictly greater than $\aleph_0$: that is, $\mathfrak c$ is uncountable. The Continuum hypothesis states that the cardinality of the continuum is the first uncountable cardinal number, that is,
$$\mathfrak c=\aleph_1 \ .$$
References
[1] | K. Kuratowski, A. Mostowski, "Set theory" , North-Holland (1968) |
Continuum, cardinality of the. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Continuum,_cardinality_of_the&oldid=33006