Linearly-disjoint extensions
2010 Mathematics Subject Classification: Primary: 12Fxx [MSN][ZBL]
Two subextensions $A$ and $B$ of an extension $\def\O{\Omega}\O$ of $k$ are called linearly disjoint if the
subalgebra generated by $A$ and $B$ in $\O$ is (isomorphic to) the
tensor product $A\otimes B$ over $k$ (cf.
Extension of a field). Let $A$ and $B$ be
arbitrary subrings of an extension $\O$ of $k$, containing $k$, and let
$C$ be the subring of $\O$ generated by $A$ and $B$. There is always a
ring homomorphism $\phi:A\otimes B \to C$ that associates with an element $x\otimes y\in A\otimes B$, $x\in A$, $y\in B$,
the product $xy$ in $C$. The algebras $A$ and $B$ are said to be
linearly disjoint over $k$ if $\phi$ is an isomorphism of $A\otimes B$ onto
$C$. In this case, $A\cap B = k$. For $A$ and $B$ to be linearly disjoint over
$k$ it is sufficient that there is a basis of $B$ over $k$ that is
independent over $A$. If $A$ is a finite extension of $k$, then the
degree of the extension $[B(A):B]$ does not exceed the degree of extension
$A:k$ and equality holds if and only if $A/k$ and $B/k$ are linearly
disjoint.
References
[Bo] | N. Bourbaki, "Algebra", Elements of mathematics, 1, Springer (1988) pp. Chapts. 4–7 (Translated from French) MR1994218 Zbl 1139.12001 |
[ZaSa] | O. Zariski, P. Samuel, "Commutative algebra", 1, Springer (1975) MR0384768 Zbl 0313.13001 |
Linearly-disjoint extensions. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Linearly-disjoint_extensions&oldid=21580