Lebesgue point

2020 Mathematics Subject Classification: Primary: 49Q15 [MSN][ZBL]

Let $f: \mathbb R^n \to \mathbb R^k$ be an absolutely locally integrable function (with respect to the Lebesgue measure $\lambda$). A Lebesgue point $x$ for $f$ is a point where \[ \lim_{r\downarrow 0} \frac{1}{\lambda (B_r (x))} \int_{B_r (x)} |f(y)-f(x)|\, dy = 0 \] Note that a Lebesgue point is, therefore, a point where $f$ is approximately continuous. Viceversa, if $f$ is essentially bounded, then any point of approximate continuity is a Lebesgue point.

The following theorem of Lebesgue holds.

Theorem 1 Let $f$ be as above. Then $\lambda$-a.e. $x$ is a Lebesgue point for $f$.

The set of Lebesgue points of $f$ is called Lebesgue set.

Comments

This concept and assertions of the type of the Lebesgue theorem lie at the foundation of various investigations of problems on convergence almost-everywhere and, in particular, of the investigations concerning singular integrals. A generalizazion is possible for Radon measures in the Euclidean space (see Differentiation of measures).

References

[KF]	A.N. Kolmogorov, S.V. Fomin, "Elements of the theory of functions and functional analysis" , 1–2 , Graylock (1957–1961)
[St]	E.M. Stein, "Singular integrals and differentiability properties of functions" , Princeton Univ. Press (1970)