Difference between revisions of "Talk:Zero-two law"
From Encyclopedia of Mathematics
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:As far as I understand, $ | \| \dots \| | $ should be $ \| | \dots | \| $, and $ |T| $ is the "linear modulus" $ T \vee (-T) $ of operator $T$ (and "$\vee$" is the lattice maximum). [[User:Boris Tsirelson|Boris Tsirelson]] ([[User talk:Boris Tsirelson|talk]]) 23:23, 18 April 2017 (CEST) | :As far as I understand, $ | \| \dots \| | $ should be $ \| | \dots | \| $, and $ |T| $ is the "linear modulus" $ T \vee (-T) $ of operator $T$ (and "$\vee$" is the lattice maximum). [[User:Boris Tsirelson|Boris Tsirelson]] ([[User talk:Boris Tsirelson|talk]]) 23:23, 18 April 2017 (CEST) | ||
| + | ::Thanks. [[User:Richard Pinch|Richard Pinch]] ([[User talk:Richard Pinch|talk]]) 08:16, 19 April 2017 (CEST) | ||
Latest revision as of 06:16, 19 April 2017
Notation
I'm not sure what the triple bar notation means here. Richard Pinch (talk) 20:12, 18 April 2017 (CEST)
- As far as I understand, $ | \| \dots \| | $ should be $ \| | \dots | \| $, and $ |T| $ is the "linear modulus" $ T \vee (-T) $ of operator $T$ (and "$\vee$" is the lattice maximum). Boris Tsirelson (talk) 23:23, 18 April 2017 (CEST)
- Thanks. Richard Pinch (talk) 08:16, 19 April 2017 (CEST)
How to Cite This Entry:
Zero-two law. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Zero-two_law&oldid=41116
Zero-two law. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Zero-two_law&oldid=41116