Difference between revisions of "Titchmarsh-Weyl m-function"
m (Fixed typo.) |
m (Marked TeXification as done.) |
||
Line 1: | Line 1: | ||
− | {{TEX| | + | {{TEX|done}} |
A function arising in an attempt to properly determine which singular boundary-value problems are self-adjoint (cf. also [[Self-adjoint differential equation|Self-adjoint differential equation]]). Begin with a formally symmetric differential expression | A function arising in an attempt to properly determine which singular boundary-value problems are self-adjoint (cf. also [[Self-adjoint differential equation|Self-adjoint differential equation]]). Begin with a formally symmetric differential expression | ||
Revision as of 10:01, 15 June 2015
A function arising in an attempt to properly determine which singular boundary-value problems are self-adjoint (cf. also Self-adjoint differential equation). Begin with a formally symmetric differential expression
where p\ne 0, q,w>0 are measurable coefficients over [a,b), and which is defined on a domain within L^2(a,b;w). The Titchmarsh–Weyl m-function is defined as follows: For \lambda = \mu + i \nu, \nu\ne 0, let \phi and \psi be solutions of L y = \lambda y satisfying
\begin{aligned} \phi(a,\lambda) &= \sin\alpha, & \psi(a,\lambda) &= \cos\alpha, \\ p\phi'(a,\lambda) &= -\cos\alpha, & p\psi'(a,\lambda) &= \sin\alpha . \end{aligned}
Now consider a real boundary condition at b', a<b'<b, of the form
\cos\beta\, x(b')+\sin\beta\, px'(b')=0,
and let \chi(x,\lambda)=\phi(x,\lambda)+\ell(\lambda)\psi(x,\lambda) satisfy it. Then
\ell(\lambda)=-\frac{\cot\beta\,\phi(b',\lambda)+p\phi'(b',\lambda)}{\cot\beta\,\psi(b'(\lambda)+p\psi'(b',\lambda)}.
If z=\cot\beta, \ell is a meromorphic function in the complex z-plane; indeed, it is a fractional-linear transformation of the z-plane into itself. From the well-known properties of fractional-linear transformations, as \beta varies over real values 0\leq\beta\leq\pi, z varies over the real z-axis, and \ell describes a circle in the z-plane.
It can be shown that if b' increases, the circles become nested. Hence there is at least one point inside all. For such a point \ell=m(\lambda),
\int\limits_a^b|\chi(x,\lambda)|^2w(x)dx<\infty.
There exists at least one solution of Ly=\lambda y, which is square-integrable.
If the limit of the circles is a point, then m(\lambda) is unique and only \chi(x,\lambda) is square-integrable. This is the limit-point case. If the limit of the circles is itself a circle, then m(\lambda) is not unique and all solutions of Ly=\lambda y are square-integrable. This is the limit-circle case.
Nonetheless, the differential operator
Ly=\frac{-(py')'+qy}{w}
whose domain satisfies
\sin\alpha\, y(a)-\cos\alpha\, py'(a)=0,
\lim_{x\to b}[p(x)(y(x)\chi'(\lambda,x)-y'(x)\chi(x,\lambda)]=0,
where \ell=m on the limit circle or limit point, is a self-adjoint differential operator (cf. also Self-adjoint operator; Self-adjoint differential equation) on L^2(a,b;w).
If the circle limit is a point, the second boundary condition (at b) is automatic.
The spectral measure of L is given by
\rho(\lambda)-\rho(\mu)=\frac1\pi\lim_{\epsilon\to0}\int\limits_\mu^\lambda\operatorname{Im}(m(\nu+i\epsilon))d\nu.
The spectral resolution of arbitrary functions in L^2(a,b;w) is
f(x) = \lim_{(\mu,\nu) \to (-\infty,\infty)} \int_\mu^\nu g(\lambda) \psi(x,\lambda) d\rho(\lambda) ,
where the limit is in the mean-square sense, and
g(\lambda)=\lim_{b'\to b}\int\limits_a^{b'}f(x)\psi(x,\lambda)dx.
References
[a1] | E.A. Coddington, N. Levinson, "Theory of ordinary differential equations" , McGraw-Hill (1955) |
[a2] | A.M. Krall, "M(\lambda) theory for singular Hamiltonian systems with one singular point" SIAM J. Math. Anal. , 20 (1989) pp. 644–700 |
Titchmarsh-Weyl m-function. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Titchmarsh-Weyl_m-function&oldid=36496