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Difference between revisions of "Leibniz formula"

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''for the derivatives of a product''
 
''for the derivatives of a product''
  
A formula that gives an expression for the <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058100/l0581001.png" />-th derivative of the product of two functions in terms of their derivatives of orders <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058100/l0581002.png" /> (the derivative of order zero is understood to be the function itself). Namely, if the functions <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058100/l0581003.png" /> and <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058100/l0581004.png" /> have derivatives up to the order <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058100/l0581005.png" /> inclusive at some point, then at this point their product <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058100/l0581006.png" /> has derivatives of the same orders, and for <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058100/l0581007.png" />,
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A formula that gives an expression for the $n$-th derivative of the product of two functions in terms of their derivatives of orders $k=0,\dots,n$ (the derivative of order zero is understood to be the function itself). Namely, if the functions $u=u(x)$ and $v=v(x)$ have derivatives up to the order $s$ inclusive at some point, then at this point their product $uv$ has derivatives of the same orders, and for $n=0,\dots,s$,
  
<table class="eq" style="width:100%;"> <tr><td valign="top" style="width:94%;text-align:center;"><img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058100/l0581008.png" /></td> </tr></table>
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$$(uv)^{(n)}=\sum_{k=0}^n\binom nku^{(k)}v^{(n-k)}.$$
  
 
This formula was communicated by G. Leibniz in a letter to J. Bernoulli in 1695.
 
This formula was communicated by G. Leibniz in a letter to J. Bernoulli in 1695.

Latest revision as of 14:16, 16 September 2014

for the derivatives of a product

A formula that gives an expression for the $n$-th derivative of the product of two functions in terms of their derivatives of orders $k=0,\dots,n$ (the derivative of order zero is understood to be the function itself). Namely, if the functions $u=u(x)$ and $v=v(x)$ have derivatives up to the order $s$ inclusive at some point, then at this point their product $uv$ has derivatives of the same orders, and for $n=0,\dots,s$,

$$(uv)^{(n)}=\sum_{k=0}^n\binom nku^{(k)}v^{(n-k)}.$$

This formula was communicated by G. Leibniz in a letter to J. Bernoulli in 1695.

How to Cite This Entry:
Leibniz formula. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Leibniz_formula&oldid=33308
This article was adapted from an original article by L.D. Kudryavtsev (originator), which appeared in Encyclopedia of Mathematics - ISBN 1402006098. See original article