Difference between revisions of "Spectral radius"
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''of an element of a Banach algebra'' | ''of an element of a Banach algebra'' | ||
− | The radius | + | The radius $\rho$ of the smallest closed disc in the plane that contains the spectrum of this element (cf. [[Spectrum of an element|Spectrum of an element]]). The spectral radius of an element $a$ is connected with the norms of its powers by the formula |
− | + | $$\rho(a)=\lim_{n\to\infty}\|a^n\|^{1/n}=\inf\|a^n\|^{1/n},$$ | |
− | which, in particular, implies that | + | which, in particular, implies that $\rho(a)\leq\|a\|$. The spectral radius of a bounded linear operator on a Banach space is the spectral radius of it regarded as an element of the Banach algebra of all operators. In a Hilbert space, the spectral radius of an operator is equal to the greatest lower bound of the norms of the operators similar to it (see [[#References|[2]]]): |
− | + | $$\rho(A)=\inf_X\|XAX^{-1}\|.$$ | |
− | If the operator is normal, then | + | If the operator is normal, then $\rho(A)=\|A\|$ (cf. [[Normal operator|Normal operator]]). |
− | As a function of the elements of a Banach algebra, the spectral radius is upper semi-continuous (but not, in general, continuous). The subharmonicity of the spectral radius has been proved [[#References|[3]]]. (This means that if | + | As a function of the elements of a Banach algebra, the spectral radius is upper semi-continuous (but not, in general, continuous). The subharmonicity of the spectral radius has been proved [[#References|[3]]]. (This means that if $z\mapsto h(z)$ is a holomorphic mapping of some domain $D\subset\mathbf C$ into a Banach algebra $\mathfrak A$, then $z\mapsto\rho(h(z))$ is a [[Subharmonic function|subharmonic function]].) |
====References==== | ====References==== |
Latest revision as of 14:46, 21 August 2014
of an element of a Banach algebra
The radius $\rho$ of the smallest closed disc in the plane that contains the spectrum of this element (cf. Spectrum of an element). The spectral radius of an element $a$ is connected with the norms of its powers by the formula
$$\rho(a)=\lim_{n\to\infty}\|a^n\|^{1/n}=\inf\|a^n\|^{1/n},$$
which, in particular, implies that $\rho(a)\leq\|a\|$. The spectral radius of a bounded linear operator on a Banach space is the spectral radius of it regarded as an element of the Banach algebra of all operators. In a Hilbert space, the spectral radius of an operator is equal to the greatest lower bound of the norms of the operators similar to it (see [2]):
$$\rho(A)=\inf_X\|XAX^{-1}\|.$$
If the operator is normal, then $\rho(A)=\|A\|$ (cf. Normal operator).
As a function of the elements of a Banach algebra, the spectral radius is upper semi-continuous (but not, in general, continuous). The subharmonicity of the spectral radius has been proved [3]. (This means that if $z\mapsto h(z)$ is a holomorphic mapping of some domain $D\subset\mathbf C$ into a Banach algebra $\mathfrak A$, then $z\mapsto\rho(h(z))$ is a subharmonic function.)
References
[1] | M.A. Naimark, "Normed rings" , Reidel (1959) (Translated from Russian) |
[2] | P.R. Halmos, "A Hilbert space problem book" , Springer (1980) |
[3] | E. Vesentini, "On the subharmonicity of the spectral radius" Boll. Union. Mat. Ital. , 1 (1968) pp. 427–429 |
[4] | V. Ptak, "On the spectral radius in Banach algebras with involution" Bull. London Math. Soc. , 2 (1970) pp. 327–334 |
Comments
References
[a1] | N. Dunford, J.T. Schwartz, "Linear operators. General theory" , 1 , Interscience (1958) |
Spectral radius. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Spectral_radius&oldid=33045