Difference between revisions of "Ermakov convergence criterion"
(Importing text file) |
|||
Line 1: | Line 1: | ||
− | + | {{MSC|40A05}} | |
+ | {{TEX|done}} | ||
− | + | A criterion for the convergence of a series $\sum_n f(n)$, where $f:[1, \infty[\to [0, \infty[$ is a monotone decreasing function, established by | |
− | + | Let <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/e/e036/e036200/e0362001.png" /> be a positive decreasing function for <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/e/e036/e036200/e0362002.png" />. If the inequality V.P. Ermakov in {{Cite|Er}}. If there is $\lambda< 1$ such that | |
− | + | \[ | |
− | + | \frac{e^x f(e^x)}{f(x)} < \lambda | |
− | + | \] | |
− | + | for sufficiently large $x$, then the series $\sum_n f(n)$ converges. If instead | |
− | + | \[ | |
− | + | \frac{e^x f(e^x)}{f(x)}\geq 1 | |
− | + | \] | |
− | + | for all sufficiently large $x$, then the series diverges. In particular the convergence or divergence of the series can be decided of the limit | |
− | + | \[ | |
− | then the series | + | \lim_{x\to\infty} \frac{e^x f(e^x)}{f(x)} |
− | + | \] | |
− | + | exists and differs from 1. | |
− | |||
− | then the series | ||
− | |||
− | |||
− | |||
− | |||
− | |||
− | |||
− | |||
+ | Ermakov's criterion can be derived from the [[Integral test|integral test]]. | ||
====References==== | ====References==== | ||
− | + | {| | |
+ | |- | ||
+ | |valign="top"|{{Ref|Br}}|| T.J. Bromwich, "An introduction to the theory of infinite series" , Macmillan (1947) | ||
+ | |- | ||
+ | |valign="top"|{{Ref|Er}}|| V.P. Ermakov, "A new criterion for convergence and divergence of infinite series of constant sign" , Kiev (1872) (In Russian) | ||
+ | |- | ||
+ | |} |
Revision as of 13:31, 10 December 2013
2020 Mathematics Subject Classification: Primary: 40A05 [MSN][ZBL]
A criterion for the convergence of a series $\sum_n f(n)$, where $f:[1, \infty[\to [0, \infty[$ is a monotone decreasing function, established by
Let be a positive decreasing function for . If the inequality V.P. Ermakov in [Er]. If there is $\lambda< 1$ such that \[ \frac{e^x f(e^x)}{f(x)} < \lambda \] for sufficiently large $x$, then the series $\sum_n f(n)$ converges. If instead \[ \frac{e^x f(e^x)}{f(x)}\geq 1 \] for all sufficiently large $x$, then the series diverges. In particular the convergence or divergence of the series can be decided of the limit \[ \lim_{x\to\infty} \frac{e^x f(e^x)}{f(x)} \] exists and differs from 1.
Ermakov's criterion can be derived from the integral test.
References
[Br] | T.J. Bromwich, "An introduction to the theory of infinite series" , Macmillan (1947) |
[Er] | V.P. Ermakov, "A new criterion for convergence and divergence of infinite series of constant sign" , Kiev (1872) (In Russian) |
Ermakov convergence criterion. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Ermakov_convergence_criterion&oldid=30931