Difference between revisions of "Galois field"
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A field with a finite number of elements. First considered by E. Galois [[#References|[1]]]. | A field with a finite number of elements. First considered by E. Galois [[#References|[1]]]. | ||
− | The number of elements of any | + | The number of elements of any finite field is a power $p^n$ of a prime number $p$, which is the [[Characteristic of a field|characteristic]] of this field. For any prime number $p$ and any natural number $n$ there exists a (unique up to an isomorphism) field of $p^n$ elements. It is denoted by $\mathrm{GF}(p^n)$ or by $\mathbb{F}_{p^n}$. The field $\mathrm{GF}(p^m)$ contains the field $\mathrm{GF}(p^n)$ as a subfield if and only if $m$ is divisible by $n$. In particular, any field $\mathrm{GF}(p^n)$ contains the field $\mathrm{GF}(p)$, which is called the [[prime field]] of characteristic $p$. The field $\mathrm{GF}(p)$ is isomorphic to the field $\mathbb{Z}/p\mathbb{Z}$ of residue classes of the ring of integers modulo $p$. In any fixed [[Algebraic closure|algebraic closure]] $\Omega$ of $\mathrm{GF}(p)$ there exists exactly one subfield $\mathrm{GF}(p^n)$ for each $n$. The correspondence $n \leftrightarrow \mathrm{GF}(p^n)$ is an isomorphism between the lattice of natural numbers with respect to division and the lattice of finite algebraic extensions (in $\Omega$) of $\mathrm{GF}(p)$ with respect to inclusion. The lattice of finite algebraic extensions of any Galois field within its fixed algebraic closure is such a lattice. |
The algebraic extension <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314026.png" /> is simple, i.e. there exists a primitive element <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314027.png" /> such that <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314028.png" />. Such an <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314029.png" /> will be any root of any irreducible polynomial of degree <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314030.png" /> from the ring <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314031.png" />. The number of primitive elements of the extension <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314032.png" /> equals | The algebraic extension <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314026.png" /> is simple, i.e. there exists a primitive element <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314027.png" /> such that <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314028.png" />. Such an <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314029.png" /> will be any root of any irreducible polynomial of degree <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314030.png" /> from the ring <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314031.png" />. The number of primitive elements of the extension <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/g/g043/g043140/g04314032.png" /> equals |
Revision as of 06:37, 31 August 2013
finite field
A field with a finite number of elements. First considered by E. Galois [1].
The number of elements of any finite field is a power $p^n$ of a prime number $p$, which is the characteristic of this field. For any prime number $p$ and any natural number $n$ there exists a (unique up to an isomorphism) field of $p^n$ elements. It is denoted by $\mathrm{GF}(p^n)$ or by $\mathbb{F}_{p^n}$. The field $\mathrm{GF}(p^m)$ contains the field $\mathrm{GF}(p^n)$ as a subfield if and only if $m$ is divisible by $n$. In particular, any field $\mathrm{GF}(p^n)$ contains the field $\mathrm{GF}(p)$, which is called the prime field of characteristic $p$. The field $\mathrm{GF}(p)$ is isomorphic to the field $\mathbb{Z}/p\mathbb{Z}$ of residue classes of the ring of integers modulo $p$. In any fixed algebraic closure $\Omega$ of $\mathrm{GF}(p)$ there exists exactly one subfield $\mathrm{GF}(p^n)$ for each $n$. The correspondence $n \leftrightarrow \mathrm{GF}(p^n)$ is an isomorphism between the lattice of natural numbers with respect to division and the lattice of finite algebraic extensions (in $\Omega$) of $\mathrm{GF}(p)$ with respect to inclusion. The lattice of finite algebraic extensions of any Galois field within its fixed algebraic closure is such a lattice.
The algebraic extension is simple, i.e. there exists a primitive element such that . Such an will be any root of any irreducible polynomial of degree from the ring . The number of primitive elements of the extension equals
where is the Möbius function. The additive group of the field is naturally endowed with the structure of an -dimensional vector space over . As a basis one may take . The non-zero elements of form a multiplicative group, , of order , i.e. each element of is a root of the polynomial . The group is cyclic, and its generators are the primitive roots of unity of degree , the number of which is , where is the Euler function. Each primitive root of unity of degree is a primitive element of the extension , but the converse is not true. More exactly, out of the
irreducible unitary polynomials of degree over there are polynomials of which the roots are generators of .
The set of elements of coincides with the set of roots of the polynomial in , i.e. is characterized as the subfield of elements from that are invariant with respect to the automorphism , which is known as the Frobenius automorphism. If , the extension is normal (cf. Extension of a field), and its Galois group is cyclic of order . The automorphism may be taken as the generator of .
References
[1] | E. Galois, "Écrits et mémoires d'E. Galois" , Gauthier-Villars (1962) |
[2] | B.L. van der Waerden, "Algebra" , 1–2 , Springer (1967–1971) (Translated from German) |
[3] | N.G. [N.G. Chebotarev] Tschebotaröw, "Grundzüge der Galois'schen Theorie" , Noordhoff (1950) (Translated from Russian) |
[4] | N. Bourbaki, "Algebra" , Elements of mathematics , 1 , Springer (1989) pp. Chapt. 1–3 (Translated from French) |
Galois field. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Galois_field&oldid=30280