Difference between revisions of "Symmetric algebra"
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For any homomorphism $f:M \to N$ of $A$-modules, the $p$-th tensor power $T^p(f)$ induces a homomorphism $S^p(f) : S^p(M) \to S^p(N)$ (the $p$-th symmetric power of the homomorphism $f$). A homomorphism $S(f) : S(M) \to S(N)$ of $A$-algebras is obtained. The correspondences $f \mapsto S^p(f)$ and $f \mapsto S(f)$ are, respectively, covariant functors from the category of $A$-modules into itself and into the category of $A$-algebras. For any two $A$-modules $M$ and $N$ there is a natural isomorphism $S(M\oplus N) = S(M) \otimes_A S(N)$. | For any homomorphism $f:M \to N$ of $A$-modules, the $p$-th tensor power $T^p(f)$ induces a homomorphism $S^p(f) : S^p(M) \to S^p(N)$ (the $p$-th symmetric power of the homomorphism $f$). A homomorphism $S(f) : S(M) \to S(N)$ of $A$-algebras is obtained. The correspondences $f \mapsto S^p(f)$ and $f \mapsto S(f)$ are, respectively, covariant functors from the category of $A$-modules into itself and into the category of $A$-algebras. For any two $A$-modules $M$ and $N$ there is a natural isomorphism $S(M\oplus N) = S(M) \otimes_A S(N)$. | ||
− | If | + | If $M$ is a vector space over a field of characteristic 0, then the [[Symmetrization (of tensors)|symmetrization]] $\sigma : T(M) \to T(M)$ defines an isomorphism from the symmetric algebra $S(M)$ onto the algebra $\tilde S(M) \subset T(M)$ of symmetric contravariant tensors over $M$ relative to symmetric multiplication: |
− | + | $$ | |
− | + | x \vee y = \sigma(x \otimes y)\,,\ \ \ x \in \tilde S^p(M)\,,\ \ y \in \tilde S^q(M) \ . | |
+ | $$ | ||
====References==== | ====References==== | ||
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====Comments==== | ====Comments==== | ||
− | The functor | + | The functor $S$ from $A$-modules to commutative unitary $A$-algebras solves the following universal problem. Let $M$ be an $A$-module and $B$ a commutative unitary $A$-algebra. For each homomorphism $f : M \to B$ of $A$-modules there is a unique homomorphism $g : S(M) \to B$ of $A$-algebras such that $g$ restricted to $S^1(M)$ coincides with $f$. Thus, $S$ is a left-adjoint functor of the underlying functor from the category of commutative unitary $A$-algebras to the category of $A$-modules. |
Latest revision as of 18:21, 11 April 2017
A generalization of a polynomial algebra. If $M$ is a unital module over a commutative associative ring $A$ with an identity, then the symmetric algebra of $M$ is the algebra $S(M) = T(M)/I$, where $T(M)$ is the tensor algebra of $M$ and $I$ is the ideal generated by the elements of the form $x \otimes y - y \otimes x$ ($x,y \in M$). A symmetric algebra is a commutative associative $A$-algebra with an identity. It is graded: $$ S(M) = \bigoplus_{p \ge 0} S^p(M) $$ where $S^p(M) = T^p(M)/(T^p(M)\cap I)$, and $S^0(M) = A$, $S^1(M) = M$. The module $S^p(M)$ is called the $p$-th symmetric power of the module $M$. If $M$ is a free module with finite basis $x_1,\ldots,x_n$, then the correspondence $x_i \mapsto X_i$ ($i=1,\ldots,n$) extends to an isomorphism of $S(M)$ onto the polynomial algebra $A[X_1,\ldots,X_n]$ (see Ring of polynomials).
For any homomorphism $f:M \to N$ of $A$-modules, the $p$-th tensor power $T^p(f)$ induces a homomorphism $S^p(f) : S^p(M) \to S^p(N)$ (the $p$-th symmetric power of the homomorphism $f$). A homomorphism $S(f) : S(M) \to S(N)$ of $A$-algebras is obtained. The correspondences $f \mapsto S^p(f)$ and $f \mapsto S(f)$ are, respectively, covariant functors from the category of $A$-modules into itself and into the category of $A$-algebras. For any two $A$-modules $M$ and $N$ there is a natural isomorphism $S(M\oplus N) = S(M) \otimes_A S(N)$. If $M$ is a vector space over a field of characteristic 0, then the symmetrization $\sigma : T(M) \to T(M)$ defines an isomorphism from the symmetric algebra $S(M)$ onto the algebra $\tilde S(M) \subset T(M)$ of symmetric contravariant tensors over $M$ relative to symmetric multiplication: $$ x \vee y = \sigma(x \otimes y)\,,\ \ \ x \in \tilde S^p(M)\,,\ \ y \in \tilde S^q(M) \ . $$
References
[1] | N. Bourbaki, "Eléments de mathématique" , 2. Algèbre , Hermann (1964) pp. Chapt. IV-VI |
[2] | A.I. Kostrikin, Yu.I. Manin, "Linear algebra and geometry" , Gordon & Breach (1989) (Translated from Russian) |
Comments
The functor $S$ from $A$-modules to commutative unitary $A$-algebras solves the following universal problem. Let $M$ be an $A$-module and $B$ a commutative unitary $A$-algebra. For each homomorphism $f : M \to B$ of $A$-modules there is a unique homomorphism $g : S(M) \to B$ of $A$-algebras such that $g$ restricted to $S^1(M)$ coincides with $f$. Thus, $S$ is a left-adjoint functor of the underlying functor from the category of commutative unitary $A$-algebras to the category of $A$-modules.
Symmetric algebra. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Symmetric_algebra&oldid=40937