Difference between revisions of "Lie bracket"
From Encyclopedia of Mathematics
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| − | The commutator of vector fields (cf. [[Vector field on a manifold|Vector field on a manifold]]) on a [[Differentiable manifold|differentiable manifold]]. If one interprets vector fields of class | + | {{TEX|done}} |
| + | The commutator of vector fields (cf. [[Vector field on a manifold|Vector field on a manifold]]) on a [[Differentiable manifold|differentiable manifold]]. If one interprets vector fields of class $C^\infty$ on a differentiable (of class $C^\infty$) manifold $M$ as derivations of the algebra $F(M)$ of functions of class $C^\infty$ on $M$, then the Lie bracket of the fields $X$ and $Y$ is given by the formula | ||
| − | + | $$[X,Y]f=X(Yf)-Y(Xf),$$ | |
| − | where | + | where $f\in F(M)$. The totality of all vector fields of class $C^\infty$ on $M$ is a [[Lie algebra|Lie algebra]] with respect to the Lie bracket. |
Latest revision as of 15:04, 13 April 2014
The commutator of vector fields (cf. Vector field on a manifold) on a differentiable manifold. If one interprets vector fields of class $C^\infty$ on a differentiable (of class $C^\infty$) manifold $M$ as derivations of the algebra $F(M)$ of functions of class $C^\infty$ on $M$, then the Lie bracket of the fields $X$ and $Y$ is given by the formula
$$[X,Y]f=X(Yf)-Y(Xf),$$
where $f\in F(M)$. The totality of all vector fields of class $C^\infty$ on $M$ is a Lie algebra with respect to the Lie bracket.
Comments
The Lie bracket of two vector fields can also be viewed as the Lie derivative of one vector field in the direction of the other.
How to Cite This Entry:
Lie bracket. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Lie_bracket&oldid=11467
Lie bracket. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Lie_bracket&oldid=11467
This article was adapted from an original article by A.L. Onishchik (originator), which appeared in Encyclopedia of Mathematics - ISBN 1402006098. See original article