Difference between revisions of "Raabe criterion"
m |
|||
(One intermediate revision by the same user not shown) | |||
Line 8: | Line 8: | ||
\frac{|a_{n+1}|}{|a_n|} \leq 1 - \frac{R}{n} | \frac{|a_{n+1}|}{|a_n|} \leq 1 - \frac{R}{n} | ||
\end{equation} | \end{equation} | ||
− | holds, then $\sum_n a_n$ converges absolutely. If instead there is $ | + | holds, then $\sum_n a_n$ converges absolutely. If instead there is $N$ such that |
\[ | \[ | ||
− | \frac{|a_{n+1}|}{|a_n|} \geq 1 - \frac{ | + | \frac{|a_{n+1}|}{|a_n|} \geq 1 - \frac{1}{n} \qquad \forall n \geq N\, , |
\] | \] | ||
− | + | then the series $\sum_n |a_n|$ diverges, which can be easily shown comparing it to the [[Harmonic series|harmonic series]]. However, the series itself might still converge, as can be seen taking | |
\[ | \[ | ||
\sum_n (-1)^n \frac{1}{\sqrt{n}}\, . | \sum_n (-1)^n \frac{1}{\sqrt{n}}\, . | ||
\] | \] | ||
− | + | The number $R$ is related to the limit | |
− | Observe | + | \[ |
+ | \lim_{n\to \infty} n \left(1-\frac{|a_n|}{|a_{n+1}|}\right) | ||
+ | \] | ||
+ | and the criterion can therefore be compared to [[Gauss criterion|Gauss' criterion]]. Observe however that the [[Harmonic series|harmonic series]] $\sum \frac{1}{n}$ (which diverges) and the series $\sum \frac{1}{n (\log n)^2}$ (which converges) have both the property that | ||
\[ | \[ | ||
\lim_{n\to \infty} n \left(1-\frac{a_n}{a_{n+1}}\right) = 1\, . | \lim_{n\to \infty} n \left(1-\frac{a_n}{a_{n+1}}\right) = 1\, . |
Latest revision as of 10:49, 10 December 2013
2020 Mathematics Subject Classification: Primary: 40A05 [MSN][ZBL]
on the convergence of a series of complex numbers
A criterion for the convergence of series of complex numbers $\sum_n a_n$, proved by J. Raabe. If $a_n \neq 0$ and there is a number $R>1$ such that for sufficiently large $n$ the inequality \begin{equation} \frac{|a_{n+1}|}{|a_n|} \leq 1 - \frac{R}{n} \end{equation} holds, then $\sum_n a_n$ converges absolutely. If instead there is $N$ such that \[ \frac{|a_{n+1}|}{|a_n|} \geq 1 - \frac{1}{n} \qquad \forall n \geq N\, , \] then the series $\sum_n |a_n|$ diverges, which can be easily shown comparing it to the harmonic series. However, the series itself might still converge, as can be seen taking \[ \sum_n (-1)^n \frac{1}{\sqrt{n}}\, . \] The number $R$ is related to the limit \[ \lim_{n\to \infty} n \left(1-\frac{|a_n|}{|a_{n+1}|}\right) \] and the criterion can therefore be compared to Gauss' criterion. Observe however that the harmonic series $\sum \frac{1}{n}$ (which diverges) and the series $\sum \frac{1}{n (\log n)^2}$ (which converges) have both the property that \[ \lim_{n\to \infty} n \left(1-\frac{a_n}{a_{n+1}}\right) = 1\, . \]
References
[Kn] | K. Knopp, "Theorie und Anwendung der unendlichen Reihen" , Springer (1964) (English translation: Blackie, 1951 & Dover, reprint, 1990) |
Raabe criterion. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Raabe_criterion&oldid=30919