# Difference between revisions of "Secretary problem"

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− | <table><TR><TD valign="top">[a1]</TD> <TD valign="top"> Y.S. Chow, H. Robbins, D. Siegmund, "The theory of optimal stopping" , Dover, reprint (1991) ( | + | <table><TR><TD valign="top">[a1]</TD> <TD valign="top"> Y.S. Chow, H. Robbins, D. Siegmund, "The theory of optimal stopping" , Dover, reprint (1991) (Original: Houghton–Mifflin, 1971)</TD></TR> |

<TR><TD valign="top">[a2]</TD> <TD valign="top"> T.S. Ferguson, "Who solved the secretary problem?" ''Statistical Science'' , '''4''' (1989) pp. 282–296</TD></TR> | <TR><TD valign="top">[a2]</TD> <TD valign="top"> T.S. Ferguson, "Who solved the secretary problem?" ''Statistical Science'' , '''4''' (1989) pp. 282–296</TD></TR> | ||

<TR><TD valign="top">[a3]</TD> <TD valign="top"> P.R. Freeman, "The secretary problem and its extensions: a review" ''Internat. Statist. Review'' , '''51''' (1983) pp. 189–206</TD></TR></table> | <TR><TD valign="top">[a3]</TD> <TD valign="top"> P.R. Freeman, "The secretary problem and its extensions: a review" ''Internat. Statist. Review'' , '''51''' (1983) pp. 189–206</TD></TR></table> |

## Latest revision as of 18:52, 11 December 2020

*best choice problem, marriage problem*

One of the best known optimal stopping problems (see also Stopping time; Sequential analysis).

A manager has the problem of selecting a secretary from a group of $n$ girls. He interviews them sequentially, one at a time, and, at each moment, can hire that particular girl. Rejected girls cannot be recalled. At each stage he knows how the present girl ranks with respect to her predecessors, but he does not know, of course, how she compares with the girls yet unseen. A rule is asked for that maximizes the chance of actually selecting the best girl.

The solution (for large $n$) is to examine and reject $p$ girls and to subsequentially choose the first girl that is better than all these $p$ girls, where the natural number $p$ is chosen such that the fraction $\frac{p}{n}$ is as close as possible to $e^{-1}$ (with $e$ the base of the natural logarithms; see also $e$ (number)). More precisely, $p$ should be chosen to maximize the expression

\[\frac{p}{n}\sum_{k=p}^{n-1} \frac{1}{k}\]

Seen as a betting game, the secretary problem is the same as the game of googol (see also Googol).

#### References

[a1] | Y.S. Chow, H. Robbins, D. Siegmund, "The theory of optimal stopping" , Dover, reprint (1991) (Original: Houghton–Mifflin, 1971) |

[a2] | T.S. Ferguson, "Who solved the secretary problem?" Statistical Science , 4 (1989) pp. 282–296 |

[a3] | P.R. Freeman, "The secretary problem and its extensions: a review" Internat. Statist. Review , 51 (1983) pp. 189–206 |

**How to Cite This Entry:**

Secretary problem.

*Encyclopedia of Mathematics.*URL: http://encyclopediaofmath.org/index.php?title=Secretary_problem&oldid=50947