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Difference between revisions of "Lie group, exponential"

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''Lie group of type <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058630/l0586302.png" />''
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''Lie group of type $(E)$''
  
A real finite-dimensional [[Lie group|Lie group]] <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058630/l0586303.png" /> for which the [[Exponential mapping|exponential mapping]] <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058630/l0586304.png" />, where <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058630/l0586305.png" /> is the [[Lie algebra|Lie algebra]] of <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/l/l058/l058630/l0586306.png" />, is a [[Diffeomorphism|diffeomorphism]].
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A real finite-dimensional [[Lie group|Lie group]] $G$ for which the [[Exponential mapping|exponential mapping]] $\exp\colon \mathfrak{g} \to G$, where $\mathfrak{g}$ is the [[Lie algebra|Lie algebra]] of $G$, is a [[Diffeomorphism|diffeomorphism]].
  
 
Any exponential Lie group is solvable and simply connected and its Lie algebra is an exponential Lie algebra (cf. [[Lie algebra, exponential|Lie algebra, exponential]]). The class of exponential Lie groups is closed with respect to passing to connected subgroups, forming quotient groups by a connected normal subgroup and forming finite direct products, but it is not closed with respect to extensions. A supersolvable Lie group (in particular, a nilpotent Lie group) is exponential if it is simply-connected (cf. [[Lie group, supersolvable|Lie group, supersolvable]])
 
Any exponential Lie group is solvable and simply connected and its Lie algebra is an exponential Lie algebra (cf. [[Lie algebra, exponential|Lie algebra, exponential]]). The class of exponential Lie groups is closed with respect to passing to connected subgroups, forming quotient groups by a connected normal subgroup and forming finite direct products, but it is not closed with respect to extensions. A supersolvable Lie group (in particular, a nilpotent Lie group) is exponential if it is simply-connected (cf. [[Lie group, supersolvable|Lie group, supersolvable]])

Revision as of 18:33, 22 January 2014

Lie group of type $(E)$

A real finite-dimensional Lie group $G$ for which the exponential mapping $\exp\colon \mathfrak{g} \to G$, where $\mathfrak{g}$ is the Lie algebra of $G$, is a diffeomorphism.

Any exponential Lie group is solvable and simply connected and its Lie algebra is an exponential Lie algebra (cf. Lie algebra, exponential). The class of exponential Lie groups is closed with respect to passing to connected subgroups, forming quotient groups by a connected normal subgroup and forming finite direct products, but it is not closed with respect to extensions. A supersolvable Lie group (in particular, a nilpotent Lie group) is exponential if it is simply-connected (cf. Lie group, supersolvable)

The intersection of connected subgroups of an exponential Lie group is connected. The centralizer of an arbitrary subset is also connected. A simply-connected Lie group is exponential if and only if it has no quotient groups containing the universal covering group of motions of the Euclidean plane as a subgroup.

References

[1] J. Dixmier, "L'application exponentielles dans les groupes de Lie résolubles" Bull. Soc. Math. France , 85 (1957) pp. 113–121
[2] M. Saitô, "Sur certains groupes de Lie résolubles I, II" Sci. Papers Coll. Gen. Educ. Univ. Tokyo , 7 (1957) pp. 1–11; 157–168


Comments

References

[a1] P. Bernal, et al., "Répresentation des groupes de Lie résolubles" , Dunod (1972)
How to Cite This Entry:
Lie group, exponential. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Lie_group,_exponential&oldid=31275
This article was adapted from an original article by V.V. Gorbatsevich (originator), which appeared in Encyclopedia of Mathematics - ISBN 1402006098. See original article