Talk:Osgood criterion

"satisfying the requirements of Definition 1"? I'd say, "satisfying Osgood's condition". --Boris Tsirelson (talk) 19:31, 28 November 2013 (CET)

Some people think of Osgood condition as the one in the displayed equation, so I would have to also relist $\omega (0) =0$ and so on. But if you think it is clear, I am fine with "satisfying Osgood's condition". Camillo (talk) 19:35, 28 November 2013 (CET)

I see. Indeed, you have a good reason to write so (even if it may be not so clear). --Boris Tsirelson (talk) 22:57, 28 November 2013 (CET)