Talk:Möbius function

The following text had been inserted into this page but was removed, because, without further explanation, its meaning is still unclear. Also, the given source is not considered in either MathSciNet or Zentralblatt für Mathematik. --Ulf Rehmann 17:38, 3 September 2013 (CEST)

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The Möbius function is related to the Riemann zeros via the formula

\begin{equation} \sum_{n=1}^{\infty}\frac{\mu(n)}{\sqrt{n}} g \log n = \sum_t \frac{h(t)}{\zeta'(1/2+it)}+2\sum_{n=1}^\infty \frac{ (-1)^{n} (2\pi )^{2n}}{(2n)! \zeta(2n+1)}\int_{-\infty}^{\infty}g(x) e^{-x(2n+1/2)} \, dx,\end{equation}

[3] Jose Javier Garcia Moreta "http://www.prespacetime.com/index.php/pst/issue/view/42 Borel Resummation & the Solution of Integral Equations