User talk:Musictheory2math

This is a true and important theory please study that carefully.

Let t=0.t(1)t(2)t(3)... ( t(k) is the k-th digit of t in the decimal system and t Should not be a rational number) be a algebraic number in the interval (0,1) of real numbers then there is a rational number in interval (0,1) of real numbers like b =0.b(1)b(2)b(3)... such that if H be a set contain h (h is in Natural numbers) that t(h)=b(h) then H is a infinite subset of Natural numbers and if t be a transcendental number then for each rational number b, the set H must be a finite set.

I guess, by t(k) you mean the k-th digit of t in the decimal system. Then, the latter cannot be true. Indeed, the number 1/9 = 0.111... is rational, thus "your" transcendental number has only finitely many digits "1". The same for 2/9 = 0.222...; only finitely many digits "2". The same for other digits: 3, 4, 5, 6, 7, 8, 9. Also for 0 (since 0 = 0.000... is a rational number). A contradiction! The infinite set cannot be covered by 10 finite sets. Boris Tsirelson (talk) 18:27, 15 March 2017 (CET)

Oops, not quite so; 9/9 = 1 = 1.000... rather than 0.999... Well, then consider the rational numbers 0.909090... and 0.090909... instead of 0.999... and 0.000... Boris Tsirelson (talk) 06:20, 16 March 2017 (CET)

A way for finding formula of prime numbers

If P be set of prime numbers and S be a set contain numbers that has been made as below:

On the beginning of each member of P put a point like 0.2 or 0.19 then S={0.2 , 0.3 , 0.5 , 0.7 , 0.11 , ... }
Now I assert that S is dense in the interval (0.1 , 1) of real numbers.
This theory is a introduction for finding formula of prime numbers.