Talk:Riesz representation theorem
From Encyclopedia of Mathematics
"Combined with the Radon-Nikodým theorem, this amounts to the following..." — really? In order to apply the Radon-Nikodým theorem we must have two measures, one absolutely continuous w.r.t. the other. But here we have only one measure $\nu$. What is the point of $\mu$ if we cannot choose it once and serve all $L$ by it? --Boris Tsirelson 21:03, 21 July 2012 (CEST)
How to Cite This Entry:
Riesz representation theorem. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Riesz_representation_theorem&oldid=27171
Riesz representation theorem. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Riesz_representation_theorem&oldid=27171