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Difference between revisions of "Talk:Arveson spectrum"

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(comments from a beginner)
 
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A rapid check shows that $\hat{x}(n)$ does not exactly satisfy the indicated equation but rather with an inverse
 
A rapid check shows that $\hat{x}(n)$ does not exactly satisfy the indicated equation but rather with an inverse
 
$$U_z \hat{x}(n) = (z)^{-1} \hat{x}(n)$$
 
$$U_z \hat{x}(n) = (z)^{-1} \hat{x}(n)$$
  
 
Even if there is no ambiguity, it would also be better if we make it clear that $\hat{x}(n)$ is still a function on $T$ (while usually in Fourier transform, the transform is a function on the "Fourier space" which I admit is just a word that doesn't explain anything)
 
Even if there is no ambiguity, it would also be better if we make it clear that $\hat{x}(n)$ is still a function on $T$ (while usually in Fourier transform, the transform is a function on the "Fourier space" which I admit is just a word that doesn't explain anything)
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A question: "vector-valued Riemann integral", is that the same thing as Bochner integrals?

Revision as of 10:53, 15 May 2014

  1. Numbered list item

A rapid check shows that $\hat{x}(n)$ does not exactly satisfy the indicated equation but rather with an inverse $$U_z \hat{x}(n) = (z)^{-1} \hat{x}(n)$$

Even if there is no ambiguity, it would also be better if we make it clear that $\hat{x}(n)$ is still a function on $T$ (while usually in Fourier transform, the transform is a function on the "Fourier space" which I admit is just a word that doesn't explain anything)

  1. Numbered list item

A question: "vector-valued Riemann integral", is that the same thing as Bochner integrals?

How to Cite This Entry:
Arveson spectrum. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Arveson_spectrum&oldid=32159