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Difference between revisions of "Talk:Osgood criterion"

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(I see)
 
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"satisfying the requirements of Definition 1"? I'd say, "satisfying Osgood's condition". --[[User:Boris Tsirelson|Boris Tsirelson]] ([[User talk:Boris Tsirelson|talk]]) 19:31, 28 November 2013 (CET)
 
"satisfying the requirements of Definition 1"? I'd say, "satisfying Osgood's condition". --[[User:Boris Tsirelson|Boris Tsirelson]] ([[User talk:Boris Tsirelson|talk]]) 19:31, 28 November 2013 (CET)
 
: Some people think of Osgood condition as the one in the displayed equation, so I would have to also relist $\omega (0) =0$ and so on. But if you think it is clear, I am fine with "satisfying Osgood's condition". [[User:Camillo.delellis|Camillo]] ([[User talk:Camillo.delellis|talk]]) 19:35, 28 November 2013 (CET)
 
: Some people think of Osgood condition as the one in the displayed equation, so I would have to also relist $\omega (0) =0$ and so on. But if you think it is clear, I am fine with "satisfying Osgood's condition". [[User:Camillo.delellis|Camillo]] ([[User talk:Camillo.delellis|talk]]) 19:35, 28 November 2013 (CET)
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:: I see. Indeed, you have a good reason to write so (even if it may be not so clear). --[[User:Boris Tsirelson|Boris Tsirelson]] ([[User talk:Boris Tsirelson|talk]]) 22:57, 28 November 2013 (CET)

Latest revision as of 21:57, 28 November 2013

"satisfying the requirements of Definition 1"? I'd say, "satisfying Osgood's condition". --Boris Tsirelson (talk) 19:31, 28 November 2013 (CET)

Some people think of Osgood condition as the one in the displayed equation, so I would have to also relist $\omega (0) =0$ and so on. But if you think it is clear, I am fine with "satisfying Osgood's condition". Camillo (talk) 19:35, 28 November 2013 (CET)
I see. Indeed, you have a good reason to write so (even if it may be not so clear). --Boris Tsirelson (talk) 22:57, 28 November 2013 (CET)
How to Cite This Entry:
Osgood criterion. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Osgood_criterion&oldid=30795