Difference between revisions of "User:Boris Tsirelson/sandbox2"
From Encyclopedia of Mathematics
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* the function $a$ is integrable if and only if the series $\sum a_n$ converges absolutely, and | * the function $a$ is integrable if and only if the series $\sum a_n$ converges absolutely, and | ||
* in this case $\int_{\{0,1,2,\dots\}} a(n)\,\mu(\rd n) = \sum_{n=0}^\infty a_n$. | * in this case $\int_{\{0,1,2,\dots\}} a(n)\,\mu(\rd n) = \sum_{n=0}^\infty a_n$. | ||
+ | The same holds when $a_n$ are complex numbers or belong to a Banach space. |
Revision as of 18:00, 21 July 2012
Relations to Lebesgue integral
It is possible to treat absolutely convergent series as a special case of Lebesgue integrals. To this end, the countable set $\{0,1,2,\dots\}$ is treated as a measure space; all subsets are measurable, and the counting measure $\mu$ is used: $\mu(A)$ is the number of points in $A$ ($\infty$ if $A$ is infinite). A sequence $(a_n)$ of real numbers is just a function $a:\{0,1,2,\dots\}\to\R$ (measurable, since everything is measurable on this discrete space). It is easy to see that
- the function $a$ is integrable if and only if the series $\sum a_n$ converges absolutely, and
- in this case $\int_{\{0,1,2,\dots\}} a(n)\,\mu(\rd n) = \sum_{n=0}^\infty a_n$.
The same holds when $a_n$ are complex numbers or belong to a Banach space.
How to Cite This Entry:
Boris Tsirelson/sandbox2. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Boris_Tsirelson/sandbox2&oldid=27156
Boris Tsirelson/sandbox2. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Boris_Tsirelson/sandbox2&oldid=27156