User talk:Musictheory2math

$Edge$ $of$ $Darkness$ (Painting theory)

Nanas lemma: If $\mathbb{P}$ is the set of prime numbers and $S$ is a set that it has been made as below: Put a point on the beginning of each member of $\Bbb{P}$ like $0.2$ or $0.19$ then $S=\{0.2,0.3,0.5,0.7,...\}$ is dense in the interval $(0.1,1)$ of real numbers.$($Nanas is my parrot and I like it so much.$)$

This lemma is a base for finding formula of prime numbers.

There is a musical note on natural numbers that it can be discovered by the formula of prime numbers.Alireza Badali 22:21, 8 May 2017 (CEST)

True, $S$ is dense in the interval $(0.1,1)$; this fact follows easily from well-known results on Distribution of prime numbers. But I doubt that this is "This lemma is a base for finding formula of prime numbers". Boris Tsirelson (talk) 22:10, 16 March 2017 (CET)

Dear Professor Boris Tsirelson , in principle finding formula of prime numbers is very lengthy. and I am not sure be able for it but please give me few time about two month for expression my theories.Alireza Badali 22:21, 8 May 2017 (CEST)

You mean, how to prove that $S$ is dense in $(0.1,1)$, right? Well, on the page "Distribution of prime numbers", in Section 6 "The difference between prime numbers", we have $ d_n \ll p_n^\delta $, where $p_n$ is the $n$-th prime number, and $ d_n = p_{n+1}-p_n $ is the difference between adjacent prime numbers; this relation holds for all $ \delta > \frac{7}{12} $; in particular, taking $ \delta = 1 $ we get $ d_n \ll p_n $, that is, $ \frac{d_n}{p_n} \to 0 $ (as $ n \to \infty $), or equivalently, $ \frac{p_{n+1}}{p_n} \to 1 $. Now, your set $S$ consists of numbers $ s_n = 10^{-k} p_n $ for all $k$ and $n$ such that $ 10^{k-1} < p_n < 10^k $. Assume that $S$ is not dense in $(0.1,1).$ Take $a$ and $b$ such that $ 0.1 < a < b < 1 $ and $ s_n \notin (a,b) $ for all $n$; that is, no $p_n$ belongs to the set \[ X = (10a,10b) \cup (100a,100b) \cup (1000a,1000b) \cup \dots \, ; \] all $ p_n $ belong to its complement \[ Y = (0,\infty) \setminus X = (0,10a] \cup [10b,100a] \cup [100b,1000a] \cup \dots \] Using the relation $ \frac{p_{n+1}}{p_n} \to 1 $ we take $N$ such that $ \frac{p_{n+1}}{p_n} < \frac b a $ for all $n>N$. Now, all numbers $p_n$ for $n>N$ must belong to a single interval $ [10^{k-1} b, 10^k a] $, since it cannot happen that $ p_n \le 10^k a $ and $ p_{n+1} \ge 10^k b $ (and $n>N$). We get a contradiction: $ p_n \to \infty $ but $ p_n \le 10^k a $. And again, please sign your messages (on talk pages) with four tildas: ~~~~. Boris Tsirelson (talk) 20:57, 18 March 2017 (CET)

'I have special thanks to Professor Boris Tsirelson for this beauty proof. Sincerely yours, Alireza Badali Sarebangholi'

Theorem $1$: For each natural number like $a=a_1a_2a_3...a_k$ that $a_j$ is $j$_th digit for $j=1,2,3,...,k$, there is a natural number like $b=b_1b_2b_3...b_r$ such that the number $c=a_1a_2a_3...a_kb_1b_2b_3...b_r$ is a prime number.Alireza Badali 22:21, 8 May 2017 (CEST)

Ah, yes, I see, this follows easily from the fact that $S$ is dense. Sounds good. Though, decimal digits are of little interest in the number theory. (I think so; but I am not an expert in the number theory.) Boris Tsirelson (talk) 11:16, 19 March 2017 (CET)

Now, assume $H$ is a mapping from $(0.1,1)$ on $(0.1,1)$ given by $H(x)=1/(10x)$.

Let $T=H(S)$, $T$ is a interesting set for its members because of, a member of $S$ like $0.a_1a_2a_3...a_n$ that $a_j$ is $j$-th digit for $j=1,2,3, ... ,n$ is basically different with ${a_1.a_2a_3a_4...a_n}^{-1}$ in $T$.

Theorem: $T$ is dense in the $(0.1,1)$.Alireza Badali 13:49, 17 May 2017 (CEST)

"Theorem: T=H(P) that P is the set of prime numbers is dense in the (0.1 , 1)." — I guess you mean H(S), not H(P). Well, this is just a special case of a simple topological fact (no number theory needed): A is dense if and only if H(A) is dense (just because H is a homeomorphism). Boris Tsirelson (talk) 18:53, 25 March 2017 (CET)

Let $D=\mathbb{Q} \cap (0.1,1)$

Dear Professor Boris Tsirelson, your help is very valuable to me and I think we can make a good paper together of course if you would like.Alireza Badali 22:21, 8 May 2017 (CEST)

Thank you for the compliment and the invitation, but no, I do not. Till now we did not write here anything really new in mathematics. Rather, simple exercises. Boris Tsirelson (talk) 18:50, 27 March 2017 (CEST)

But do not you think this way about prime numbers is new and for the first time.Alireza Badali 22:21, 8 May 2017 (CEST)

It is not enough to say that this way is new. The question is, does this way give new interesting results? Boris Tsirelson (talk) 21:03, 30 March 2017 (CEST)

Dear Professor Boris Tsirelson, I thank you so much for your valuable help to me and I owe you because I was unable for proving the Nanas lemma but you proved it seemly and guided me honestly that in principle you gave me a new hope to continue.

Assume $S_1$={ $a/10^n$ | $a\in{S}$ for $n$=$0,1,2,3,...$ } & $T_1$={ $a/10^n$ | $a\in{T}$ for $n=0,1,2,3,...$ }.

Theorem: $S_1$ and also $T_1$ are dense in the interval $(0,1)$.

Assume $T_1$ is the dual of $S_1$ so the combine of both $T_1$ and $S_1$ make us so stronger.

Let $W$={ $±(z+a)$ | $a\in{S_1 \cup T_1}$ for $z=0,1,2,3,...$ } & $G=\mathbb{Q} \setminus W$

Theorem $2$: $W$ and also $G$ are dense in the $\mathbb{Q}$ and also $\mathbb{R}$.

Conjecture: For each member of $G$ like $g$, there are two members of $W$ like $a,b$ in the interval $(g-0.5,g+0.5)$ such that $g=(a+b)/2$.

Of course it is enough that the conjecture just is proved for the interval $(0,1)$ namely assume $g\in{(0,1) \cap {G}}$.

Therefore if a continuous mapping from $D$ on $S$ is found, we must make some topological spaces by the Euclidean topology, into the $(0.1,1)×(0.1,1)$ of Euclidean plane such that some topological properties particularly around the sequences is transferred to the set $S$. And now I must say that the formula of prime numbers is equal to an unique painting in the $(0.1,1)×(0.1,1)$.

Alireza Badali 22:21, 8 May 2017 (CEST)

About Painting theory

Theorem: $S×S$ is dense in the $(0.1,1)×(0.1,1)$. Similar theorems are right for $S×T$ & $T×T$.Alireza Badali 13:49, 17 May 2017 (CEST)

"Theorem: C=S×S is dense in the (0.1 , 1)×(0.1 , 1) similar theorems is right for C=S×T and C=T×S and C=T×T." — This is also a special case of a simple topological fact: $A\times B$ is dense if and only if $A$ and $B$ are dense. Boris Tsirelson (talk) 18:53, 25 March 2017 (CET)

Theorem: $D$ and $S$ are homeomorph by the Euclidean topology.

For each member of $D$ like $w=0.a_1a_2a_3...a_ka_{k+1}a_{k+2}...a_{n-1}a_na_{k+1}a_{k+2}...a_{n-1}a_n...$ that $a_{k+1}a_{k+2}...a_{n-1}a_n$ repeats and $k=0,1,2,3,...,n$ , assume $t=a_1a_2a_3...a_ka_{k+1}...a_n00...00$ is a natural number such that $k$ up to $0$ is inserted on the beginning of $t$ , now by the induction axiom and theorem 1 , there is the least number in the natural numbers like $b_1b_2...b_r$ such that the number $a_1a_2a_3...a_ka_{k+1}...a_{n}00...00b_1b_2...b_r$ is a prime number and so $0.a_1a_2a_3...a_ka_{k+1}...a_{n}00...00b_1b_2...b_r\in{S}$.♥ But there is a big problem, where is the rule of this homeomorphism.

Theorem: $D$ and $T$ are homeomorph by the Euclidean topology.

An important question: Is there any real infinite subset of $S$ such that it is dense in the interval $(0.1,1)$ of real numbers?

Assuming $P_1$={ $p$ | $p$ is a prime number & number of digits of $p$ is a prime number } that $P_1$ is called the set of primer numbers, now whether $P_1$ is dense in the $(0.1,1)$$?$ This is a suitable definition for information security and coding theory!

Alireza Badali 22:21, 8 May 2017 (CEST)

Other problems

1) About set theory: So many years ago I heard of my friend that it has been proved that each set is order-able with total order, Is this right? and please say by who and when.Alireza Badali 22:21, 8 May 2017 (CEST)

Yes. See Axiom of choice. There, find this: "Many postulates equivalent to the axiom of choice were subsequently discovered. Among these are: 1) The well-ordering theorem: On any set there exists a total order". Boris Tsirelson (talk) 16:46, 8 April 2017 (CEST)

So is there any set with cardinal between $\aleph_0$ and $\aleph_1$ and not equal to $\aleph_0$ and $\aleph_1$, and also for $\aleph_1$ and $\aleph_2$ and so on, I think so the well-ordering theorem answers this question.Alireza Badali 22:21, 8 May 2017 (CEST)

See Continuum hypothesis. Boris Tsirelson (talk) 07:27, 9 April 2017 (CEST)

Also, did you try Wikipedia? Visit this: WP:Continuum_hypothesis. And this: WP:Project Mathematics. And WP:Reference desk/Mathematics. Boris Tsirelson (talk) 07:38, 9 April 2017 (CEST)

Dear Professor Boris Tsirelson, I thank you so much and yes I should go to the Wikipedia more and I think the well-ordering theorem results each set is exactly a line. Sincerely yours Badali

2) About ?!: The set of real numbers is dense in the whole of mathematics( whole and not set ).

3) A wonderful definition in the mathematical philosophy (and perhaps mathematical logic too): In between the all of mathematical concepts, there are some special concepts that are not logical or are in contradiction with other concepts but in the whole of mathematics a changing occurred that made mathematics logical, I define this changing the curvature of mathematical concepts.

4) About mathematical logic: Complex set theory: It seems in different sections of mathematics we connect sets to each other by function concept that of course the own function is a set with a property too, but whether function concept has itself importance as a independent and basic axiom like Axiom of Choice or not, because in mathematics every work is occurred by function, in principle the Axiom of choice or natural numbers(or real numbers and or complex numbers) or function concept are dense in the whole of mathematics, and I want offer that a set theory is made just like complex numbers that set concept is real line and function concept is imagine line. Of course I think that the own perception is a function of own human not more and not less.

5) Most important question: The formula of prime numbers what impact will create on mindset of human.

6) About physics: The time dimension is a periodic phenomenon.

7) Artificial intelligence is the ability to lying without any goofs of course only for a limited time.

8) Each mathematical theory is a graph or a hyper graph.

9) Mathematical logic is the language of Mathematics(There is not any difference between language of Mathematics and English literature or Persian literature or each other language, because both Mathematical and literary just state statements about some subjects and each one by own logical principles, of course language of Mathematics is very elementary till now compared with literature of a language and must be improved.) and Mathematical philosophy is the way of thinking about Mathematics, always there was a special relationship between Mathematical philosophy and Mathematical logic, but nobody knows which one is first and basic, and there is no boundary between them, however, weakness of Mathematics is from 1) disagreement between the Mathematical philosophy and the Mathematical logic(Of course whatever this disagreement is decreased, equally Mathematics grows.) and 2) weakness of own Mathematical logic, but music can be help to removing this problem, because of everything has harmony is a music too, In principle I want say that whatever this disagreement between expression and thinking is decreased equally Mathematics grows.

10) The Goldbach`s conjecture is a way for finding formula of prime numbers!

Alireza Badali 22:21, 8 May 2017 (CEST)

A new version of Goldbach`s conjecture

Goldbach's conjecture is one of the oldest and best-known unsolved problems in number theory and all of mathematics. It states: Every even integer greater than $2$ can be expressed as the sum of two primes.

Nanas lemma: If $\mathbb P$ is the set of prime numbers and $S$ is a set that it has been made as below: put a point on the beginning of each member of $\mathbb P$ like $0.2$ or $0.19$ then $S=\{0.2,0.3,0.5,0.7,...\}$ is dense in the interval $(0.1,1)$ of real numbers.

Proof is given by Professor Boris Tsirelson, here.

Theorem $1$: For each natural number like $a=a_1a_2a_3...a_k$ that $a_j$ is $j$_th digit for $j=1,2,3,...,k$, there is a natural number like $b=b_1b_2b_3...b_r$ such that the number $c=a_1a_2a_3...a_kb_1b_2b_3...b_r$ is a prime number.

Assume $S_1$={ $a/10^n$ | $a\in{S}$ for $n$=$0,1,2,3,...$ } & $L$={ $10^m \times (a/2+b/2)$ | $a,b \in S_1$ such that if $a(or b) \in (0,0.1)$ then $b(or a) \notin (0,0.1)$ & $a=a_1a_2a_3...a_m$ & $b=b_1b_2b_3...b_m$ & $m \in \Bbb{N}$ }

Theorem: $S_1$ is dense in the interval $(0,1)$.

Conjecture $1$: For each rational number with a finite sequence like $t=0.t_1t_2t_3...t_m$ (not needed $t_i≠0$ for $i=1,2,3,...,m$) that $t\in(0.01,1)$, then there are two members of $S_1$ like $a,b$ such that $t=(a+b)/2$ & $10^m \times a$, $10^m \times b$ are prime numbers.

Conjecture $2$: $L= \Bbb{N}$

These conjectures are new versions of Goldbach`s conjecture.

Assuming correctness the new versions of Goldbach`s conjecture, it is a way for finding formula of prime numbers, because it explains behavior of prime numbers!

Alireza Badali 13:39, 24 May 2017 (CEST)

"On the co(girth) of a connected matroid"

Strangely, I see three authors of that work: Jung Jin Cho, Yong Chen, Yu Ding (rather than Alireza Badali). But you wrote it is your thesis. Do I misunderstand something? Boris Tsirelson (talk) 16:10, 19 May 2017 (CEST)

Dear Professor Boris Tsirelson, my mean was this that I have worked on this paper as a thesis only, of course I have not written it, my English is so weak, okay I must edit it, and I thank you for this right point.Alireza Badali 17:45, 19 May 2017 (CEST)