View source for Talk:Tight measure

"On a locally compact space $X$ such measures are also outer regular" – really? Even if the space is not separable, like (0,1) times a uncountable discrete space? --[[User:Boris Tsirelson|Boris Tsirelson]] ([[User talk:Boris Tsirelson|talk]]) 09:37, 30 November 2012 (CET)
:No, if the $\sigma$-algebra generated by the compact sets does not coincide with the Borel $\sigma$-algebra, then there are counterexamples. I missed that the references claiming this fact without assuming separability of the space assume anyway finiteness of the measure. [[User:Camillo.delellis|Camillo]] ([[User talk:Camillo.delellis|talk]]) 13:05, 30 November 2012 (CET)