Inverse mapping
(inverse operator) of a single-valued onto mapping (operator)
![]() |
A single-valued mapping such that
![]() | (1) |
![]() | (2) |
where ,
and
are any sets.
If satisfies only condition (1), then it is called a left-inverse mapping of
, and if it satisfies only condition (2), it is a right-inverse mapping of
. The inverse mapping
exists if and only if for each
the complete inverse image
consists of a single element
. If
has an inverse mapping
, then the equation
![]() | (3) |
has a unique solution for each . If only a right inverse
exists, then a solution of (3) exists, but its uniqueness is an open question. If only a left inverse
exists, then the solution is unique, assuming that it exists. If
and
are vector spaces and if
is a linear operator from
into
, then
is also linear, if it exists. In general, if
and
are endowed with some kind of structure, it may happen that certain properties of
are also inherited by
, assuming that it exists. E.g., if
and
are Banach spaces and
is a closed operator, then
is also closed; if
is a Hilbert space and
is self-adjoint, then
is also self-adjoint; if
is an odd function, then
is also odd, etc. The continuity of
does not always imply the continuity of
for many important classes of linear operators, for example for completely-continuous operators. The following are important tests for the continuity of the inverse of a linear operator.
Let be a finite-dimensional vector space, with a certain basis, and let
be given by the matrix
with respect to this basis. Then
exists if and only if
(in this case
and
are automatically continuous).
Let and
be Banach spaces, and let
be a continuous linear operator from
into
.
1) If , where
, then
exists and is continuous.
2) If ,
, then
exists, is continuous and
![]() |
where the series on the right-hand side converges in the norm of the space .
3) The operator exists and is continuous on all of
if and only if the conjugate
has an inverse which is defined and continuous on
. Here
.
4) If exists, is continuous and if
, then
also exists, is continuous and
![]() |
Thus, the set of invertible operators is open in in the uniform topology of this space.
5) Banach's open mapping theorem: If is a one-to-one mapping of
onto
, then the inverse mapping, which exists, is continuous. This theorem has the following generalization: A one-to-one continuous linear mapping of a fully-complete space
onto a separated barrelled space
is a topological isomorphism.
The spectral theory of linear operators on a Hilbert space contains a number of results on the existence and continuity of the inverse of a continuous linear operator. E.g., if is self-adjoint and
is not real, then
exists and is continuous.
References
[1] | N. Dunford, J.T. Schwartz, "Linear operators. General theory" , 1 , Interscience (1958) |
[2] | L.V. Kantorovich, G.P. Akilov, "Functional analysis" , Pergamon (1982) (Translated from Russian) |
[3] | W. Rudin, "Functional analysis" , McGraw-Hill (1979) |
[4] | A.P. Robertson, W.S. Robertson, "Topological vector spaces" , Cambridge Univ. Press (1964) |
Inverse mapping. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Inverse_mapping&oldid=15880